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I have a xml.in this xml I have a node named video like below 

  <product>
 <id>676872</id>
  <weightingram>510</weightingram>
  <volume>0</volume>
  <discountgroup />
 <name>Product name (500 g)</name>
  <vat>10,49</vat>
  <webbestprice extra="webbestprice">0</webbestprice>
  <webreturn extra="webreturn">0</webreturn>
  <weboutdate extra="weboutdate">01-01-2013 00:00:00</weboutdate>
  <webaltitem extra="webaltitem" />
  <filters extra="filters">
    <ISP_WebItem FILTER="Type" FILTERNAME="type" UNITCODE=""/>
    <ISP_WebItem FILTER="Type2" FILTERNAME="500" UNITCODE="g"/>
  </filters>
  <videos extra="videos">
    <YoutubeVideoURL RowNumber="33" ProductID="676872" YoutubeUrl="http://www.youtube.com/watch?v=EjoEIHVk9qM" YoutubeImage="https://img.youtube.com/vi/EjoEIHVk9qM/2.jpg"/>
  </videos>
</product>

the above xml is getting by using

<textarea>
<xsl:copy-of select="."/>
</textarea>

I need to get the value of attribute YoutubeUrl from this xml.I tried something like

 <xsl:value-of select="./videos/YoutubeVideoURL[@YoutubeUrl] "/>

but it is not working.Thanks in advance for help.

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4
  • You need to show more context in your XSL, one cannot guess at what context your are executing the xsl:value-of and therefore cannot even guess at what your problem is. Show the whole template. Commented Oct 4, 2013 at 5:25
  • I agree with @KevinBrown that you should have to provide your working XML contents so that others can get idea. Commented Oct 4, 2013 at 6:15
  • @Matthew Green please find the edit Commented Oct 4, 2013 at 11:18
  • @Arun; i have updated my ans an tested. Its retriving the value properly...Let me know what template you have set to retrive the YoutubeUrl value Commented Oct 4, 2013 at 17:36

3 Answers 3

Reset to default
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You can write like this

Your sample XML file

<?xml version="1.0" encoding="UTF-8"?>
<videos extra="videos">
    <YoutubeVideoURL RowNumber="1" ProductID="12452" YoutubeUrl="http://www.youtube.com/watch?v=efhrtgdbo" YoutubeImage="https://img.youtube.com/vi/efhrtgdbo/2.jpg"/>
</videos>

And your sample XSL file

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml"/>
    <xsl:template match="YoutubeVideoURL">
        <xsl:value-of select="@YoutubeUrl"/>
    </xsl:template>
</xsl:stylesheet>

Final output

http://www.youtube.com/watch?v=efhrtgdbo

That's it

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4 Comments

But I have the xslt,in this xslt <xsl:template match="product"> here i get the sample xml as i given in the question.here I need to get the YoutubeUrl value. </xsl:template>
But you provided only </video> xml. So based on your sample I can only provide that answer. You have to show your working XML.
It is correct ..I said I can't call <xsl:template match="YoutubeVideoURL"> inside <xsl:template match="product">
Try with this if you can access as per your XML structure : <xsl:value-of select="./videos/YoutubeVideoURL/@YoutubeUrl"/>
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Try this code

<xsl:template match="YoutubeVideoURL">
   <xsl:value-of select="@YoutubeUrl"/>
</xsl:template>

(or)

if you have specified the template that is matching to "/" root then use the below syntax.

<xsl:template match="/">

 .....
   <textarea>
      <xsl:copy-of select="." />
   </textarea>
   <p>
   <xsl:value-of select="//videos//YoutubeVideoURL//@YoutubeUrl"/>
   </p>
</xsl:template>

Copy-of will copy the xml element specified in the select expression. So TextArea will have that xml element with its structure. And you are using value-of to retrive the xml attribute which needs an element selection. So, its not related.

You can use either of the solution mentioned in this ans.

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5 Comments

I tried the second one .but not working. <xsl:value-of select="./videos/YoutubeVideoURL@YoutubeUrl"/>
can you try without "./"? Start from videos. And did you tried the first one?
<xsl:value-of select="videos/YoutubeVideoURL@YoutubeUrl"/>
@Viji Your second example is not a valid XPath expression. You are missing a /.
@Arun: You can use this <xsl:value-of select="videos/YoutubeVideoURL/@YoutubeUrl"/> , I missed / in that.
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In your value-of you are looking for any videos/YoutubeVideoURL that have an attribute of @YoutubeUrl. If you are looking to get the value of @YoutubeUrl then you need to take it out of the predicate like so.

<xsl:value-of select="./videos/YoutubeVideoURL/@YoutubeUrl" />

This of course assumes that your paths and templates are already set up correctly to locate this value at it's current position.

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4 Comments

Yes When i Test <<xsl:value-of select="./videos> it get the result.. <YoutubeVideoURL RowNumber="29" ProductID="80182" YoutubeUrl="youtube.com/watch?v=EjoEIHVk9qM" YoutubeImage="img.youtube.com/vi/EjoEIHVk9qM/2.jpg"> but Trying <xsl:value-of select="./videos/YoutubeVideoURL/@YoutubeUrl" /> it dosn't give any result? What is the Problem?
@Arun I don't know what the issue is without you providing more of your XML and XSL. When I take what you've shown for XML and transform it with my XSL that looks for the value I've specified I get the URL. Is the XML you've shown in an actual XML and not a result tree fragment?
yes I edited question please find.the xml is getting while <textarea><xsl:copy-of select="."/></textarea>
@Arun so you are copying the XML into a <textarea>? I'm not sure I understand. Can you show more of the XSL? That might help narrow down the problem. I think your XML must be a RTF but it's hard to tell based on the information. Of course this all assumes you are using XSLT 1.0 too.

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