I have a string like:
{"Url":"http://localhost","DBName":"John_db","DBUser":"admin","Pass":"a"}
Now using this string I want URL, DBname, DBuser and pass them to separate variables like:
$DBName = 'John_db';
$DBUser = 'admin';
$Url = 'http://localhost';
$Pass = 'a';
I am new to PHP, and can't find any solution to achieve this, can anybody help me in this?
You don't really need to split each one into individual variables. You could just decode that JSON into an array or object:
$str = '{"Url":"http://localhost","DBName":"John_db","DBUser":"admin","Pass":"a"}';
$arr = json_decode( $str, true );
Now you have an associative array containing all of the variables:
Array(
[ Url ] => "http://localhost",
[ DBName ] => "John_db",
...
)
If you don't specify the second parameter to json_decode(), you'll get a regular object:
$obj = json_decode( $str );
echo $obj->Url; // http://localhost
echo $obj->DBName; // John_db
References -
true to json_decode(). Then you'll be able to access that value by using: $arr[ "DB Name" ]."This string" is JSON object. Use json_decode() to get array with all values and then get it from there.
$str = '{"Url":"http://localhost","DBName":"John_db","DBUser":"admin","Pass":"a"}';
$out = json_decode( $str, true );
and $out ends like:
Array
(
[Url] => http://localhost
[DBName] => John_db
[DBUser] => admin
[Pass] => a
)
$ar = json_decode( '{"Url":"http://localhost","DBName":"John_db","DBUser":"admin","Pass":"a"}', 1 );
foreach ($ar as $k => $a) {
$$k = $a;
}
Now you should have your vars filled.
Working code here: http://codepad.org/Do9ixqfN
list(), but that's over complicating things...Use json_decode function like this:
<?
$string = '{"Url":"http://localhost","DBName":"John_db","DBUser":"admin","Pass":"a"}';
$array = json_decode( $string, true );
print_r($array);
?>
That string is a JSON object and you can use json_decode to convert that string into an associative array.
