Run 3 python scripts using bash

Question

I want to be able to accomplish the following. Run script(1)-->sleep 5-->run script(2)-->sleep 5. This pattern needs to continue for the next 30 minutes before running script(3). Once all 3 scripts are run, they need to loop again in the same fashion.

I have no clue what I'm doing, I know it involves a while loop with a counter, etc. I don't know if this is correct and I don't know where to place script3.py. This is what I have so far:

#!/bin/bash
while true;
i=0
until [ i$ -eq 36]
do 
    python script1.py
    sleep 5
    python script2.py
    sleep 5      
    i=$[$i+1]
python script3.py
done

Thanks for any feedback! Damo

If you can't write bash scripts then write your code here in Python! — user2665694
– user2665694, Commented Oct 11, 2013 at 4:37

Curt · Accepted Answer · 2013-10-11 04:46:36Z

3

I'm kind of surprised this question got so many downvotes. Anyway, this is what you want

#!/bin/bash
while true
do
    begin_time=$(date +%s)
    end_time=$((begin_time + 30*60))
    while [ $(date +%s) -lt $end_time ]
    do
        python script1.py
        sleep 5
        python script2.py
        sleep 5
    done
    python script3.py
 done

answered Oct 11, 2013 at 4:46

Curt

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1 Comment

user2081594 Over a year ago

Thanks Kurtis, I'm not a programmer and as such have very little experience who asks dumb questions, so I'm not surprised by the downvotes. However, what you suggested works perfectly :)

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