Get HTTP Error code from requests.exceptions.HTTPError

Question

I am catching exceptions like this,

def get_url_fp(image_url, request_kwargs=None):
    response = requests.get(some_url, **request_kwargs)
    response.raise_for_status()
    return response.raw


try:
   a = "http://example.com"
   fp = get_url_fp(a)

except HTTPError as e:
    # Need to check its an 404, 503, 500, 403 etc.

Maybe this post would be helpful: stackoverflow.com/a/16206247/1461780 — Leon Young
– Leon Young, Commented Oct 13, 2013 at 5:35

Lukasa · Accepted Answer · 2013-10-13 08:10:15Z

183

The HTTPError carries the Response object with it:

def get_url_fp(image_url, request_kwargs=None):
    response = requests.get(some_url, **request_kwargs)
    response.raise_for_status()
    return response.raw


try:
    a = "http://example.com"
    fp = get_url_fp(a)

except HTTPError as e:
    # Need to check its an 404, 503, 500, 403 etc.
    status_code = e.response.status_code

answered Oct 13, 2013 at 8:10

Lukasa

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3 Comments

nommer Over a year ago

one of the keys here is you also need to call response.raise_for_status(). reference here: docs.python-requests.org/en/latest/user/quickstart/…

Gokul Over a year ago

Thanks a ton. Seems like this is the only way to handle errors in any HTTP methods using python requests.

Edward Falk Over a year ago

Curious. I'm seeing e.response as an object of type urllib3.response.HTTPResponse.

calraiden · Accepted Answer · 2022-07-20 14:00:40Z

13

If you need only status_code or message error. You can use this code:

try:
  [YOUR CODE]
except requests.exceptions.HTTPError as err:
  print(err.response.status_code)
  print(err.response.text)

Reference: Source code for requests.exceptions

answered Jul 20, 2022 at 14:00

calraiden

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Comments

Raj · Accepted Answer · 2017-09-13 03:13:12Z

-10

This is my code to get errors codes in HTTP

def tomcat_status(ip,port,url):
    try:
    # you can give your own url is
       r = urllib2.urlopen('http://'+ip+':'+port+'/'+url)
       return r.getcode()
     except urllib2.HTTPError as e:
       return e.code
    except urllib2.URLError as f:
       return 1
print tomcat_status(ip,tomcat_port,ping_url)

edited Sep 13, 2017 at 3:13

answered Jun 14, 2017 at 8:39

Raj

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2 Comments

e.thompsy Over a year ago

The OP was specific about using the Requests package. Your answer is using urllib2. While it may be technically accurate and represent an alternative way to do a thing it is not helpful in this context. It also appears to be poorly formatted.

Raj Over a year ago

This is just another alternative to get the Status code, as both request and urllib are default in python , we can use either of them.

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