Array JSON in javascript

Question

My json is:

[
   {
      "_id":{
         "time":1381823399000,
         "new":false,
         "timeSecond":1381823399,
         "machine":263168773,
         "inc":-649466399
      },
      "asset":"RO2550AS1",
      "Salt Rejection":"90%",
      "Salt Passage":"10%",
      "Recovery":"59%",
      "Concentration Factor":"2.43",
      "status":"critical",
      "Flow Alarm":"High Flow"
   },
   [
      {
         "Estimated Cost":"USD 15",
         "AssetName":"RO2500AS1",
         "Description":"Pump Maintenance",
         "Index":"1",
         "Type":"Service",
         "DeadLine":"13 November 2013"
      },
      {
         "Estimated Cost":"USD 35",
         "AssetName":"RO2500AS1",
         "Description":"Heat Sensor",
         "Index":"2",
         "Type":"Replacement",
         "DeadLine":"26 November 2013"
      },
      {
         "Estimated Cost":"USD 35",
         "AssetName":"RO2550AS1",
         "Description":"Heat Sensor",
         "Index":"3",
         "Type":"Replacement",
         "DeadLine":"26 November 2013"
      },
      {
         "Estimated Cost":"USD 15",
         "AssetName":"RO2550AS1",
         "Description":"Pump Maintenance",
         "Index":"4",
         "Type":"Service",
         "DeadLine":"13 November 2013"
      },
      {
         "Estimated Cost":"USD 15",
         "AssetName":"RO3000AS1",
         "Description":"Pump Maintenance",
         "Index":"5",
         "Type":"Service",
         "DeadLine":"13 November 2013"
      },
      {
         "Estimated Cost":"USD 35",
         "AssetName":"RO3000AS1",
         "Description":"Heat Sensor",
         "Index":"6",
         "Type":"Replacement",
         "DeadLine":"26 November 2013"
      }
   ]
]

I need to access it in javascript.

The following code is not working:

var jsonobjstr = JSON.parse(jsonOutput);
alert ("asset: "+jsonobjstr.asset);

What is jsonOutput set to? Do you have any error messages appearing in the console? — Paul S.
– Paul S., Commented Oct 15, 2013 at 18:29
Hint: you are passing Json inside of an array, treat it as such — Jose
– Jose, Commented Oct 15, 2013 at 18:31

Explosion Pills · Accepted Answer · 2013-10-15 18:29:58Z

4

Because the entire JSON is contained in an array.

alert("asset: "+jsonobjstr[0].asset);

http://jsfiddle.net/ExplosionPIlls/yHj5X/2/

answered Oct 15, 2013 at 18:29

Explosion Pills

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lolol · Accepted Answer · 2013-10-15 18:53:52Z

2

In javascript

var somename = []; means a new array and; var somename = {}; means a new object.

Therefore if some json starts with a [] means it is a array of objects, and if it starts with {} means it is a object.

Your json starts with [], therefore it is a array of objects, so you need to access each object by doing:

json[n].asset for each position of the array (where n is a integer).

BUT:

Your JSON is weird. Looks like you will always have a array with one element (if true, the json should start with {}.

LIKE:

{
    "id":
    {
        "code":1381823399000
    },
    "asset":"RO2550AS1",
    "history":
    [
        {
            "value":"USD 15"
        },
        {
            "value":"USD 15"
        },
        {
            "value":"USD 15"
        }
    ]
 }

Here you can do:

thing.id.code
thing.asset
thing.history[0].value
thing.history[1].value

edited Oct 15, 2013 at 18:53

answered Oct 15, 2013 at 18:33

lolol

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3 Comments

Kiruse Over a year ago

I disagree with your BUT: He's passing an array with 1 object followed by another array of objects containing uniform information.

lolol Over a year ago

There is nothing to disagree. If the parent object is not an array, why treat it like so? Look at the example.

Kiruse Over a year ago

Of course there is something to disagree. Your statement did not say anything at all about "wrapping" the uniform information in a separate property prior to your edit. Without the example to clarify your intention, your statement is simply false, or perhaps incomplete. Regardless, debates are against the rules.

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