<?php
function dosomething(){
echo "do\n";
}
$temp="test".dosomething();
echo $temp;
?>
expected result:testdo
but actual result is: do
test%
I know how to change the code to get the expected result. But what i doubt is why the code prints result like this. Can someone explain it?Thanks!
dosomething is echoing to the screen. Since this runs first "do\n" is printed.
dosomething also doesn't return anything so the second echo is equivalent to echo "test";
In order to use the result of the call you should return it:
function dosomething(){
return "do\n";
}
Which will behave as you expect.
To clarify. In order to work out what $temp is the function must be run first which prints out "do\n" first.
Use return.
function dosomething(){
return "do\n"; }
Use a return statement instead of echo
function dosomething(){
return "do\n";
}
I'm not sure why people are getting down voted. Their answers are right.
Try this:
Use return in the calling function. Doing that you will get the string where the function is being called. So function is being replaced by string and 2 strings will then con cat.
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Thanks
