How to handle Pop-up in Selenium WebDriver using Java

Question

I want to handle sign-in part in rediff.com, but the below code doesn't work for that:

driver.get("http://www.rediff.com/");
WebElement sign = driver.findElement(By.xpath("//html/body/div[3]/div[3]/span[4]/span/a"));
sign.click();
String myWindowHandle = driver.getWindowHandle();
driver.switchTo().window(myWindowHandle);
WebElement email_id= driver.findElement(By.xpath("//*[@id='signin_info']/a[1]"));
email_id.sendKeys("hi");

If myWindowHandle is not the correct string, then let me know how to get the pop-up Window name, because I can't find the name of the pop-up window.

Take the list of windows by using driver.getWindowHandles(). — Ripon Al Wasim
– Ripon Al Wasim, Commented Aug 29, 2017 at 11:22

LINGS · Accepted Answer · 2017-06-03 17:45:29Z

45

To switch to a popup window, you need to use getWindowHandles() and iterate through them.

In your code you are using getWindowHandle() which will give you the parent window itself.

String parentWindowHandler = driver.getWindowHandle(); // Store your parent window
String subWindowHandler = null;

Set<String> handles = driver.getWindowHandles(); // get all window handles
Iterator<String> iterator = handles.iterator();
while (iterator.hasNext()){
    subWindowHandler = iterator.next();
}
driver.switchTo().window(subWindowHandler); // switch to popup window

// Now you are in the popup window, perform necessary actions here

driver.switchTo().window(parentWindowHandler);  // switch back to parent window

edited Jun 3, 2017 at 17:45

answered Oct 16, 2013 at 16:46

LINGS

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4 Comments

Niyati Over a year ago

But i just need to handle only one window than i think so no meaning to use iterator ...do u have another way . i just need to write email address and password in sign in form of rediff.com .pls helm me in this .

LINGS Over a year ago

The above code will handle that. Once you switch to sub window which is your popup. Pick the webelements and fill in your email id, password and submit. Then switch back to your parent window.

Niyati Over a year ago

Tried but code is not working on link : rediff.com -> click on sign in link and try to signed in

Hovercraft Full Of Eels Over a year ago

@Johnp2: please don't hijack the answer

Seanny123 · Accepted Answer · 2013-10-17 07:39:47Z

I found the solution for the above program, which had the goal of signing in to http://rediff.com

public class Handle_popupNAlert
{
    public static void main(String[] args ) throws InterruptedException
    {
        WebDriver driver= new FirefoxDriver(); 
        driver.get("http://www.rediff.com/");
        WebElement sign = driver.findElement(By.xpath("//html/body/div[3]/div[3]/span[4]/span/a"));
        sign.click();

        Set<String> windowId = driver.getWindowHandles();    // get  window id of current window
        Iterator<String> itererator = windowId.iterator();   

        String mainWinID = itererator.next();
        String  newAdwinID = itererator.next();

        driver.switchTo().window(newAdwinID);
        System.out.println(driver.getTitle());
        Thread.sleep(3000);
        driver.close();

        driver.switchTo().window(mainWinID);
        System.out.println(driver.getTitle());
        Thread.sleep(2000);

        WebElement email_id= driver.findElement(By.xpath("//*[@id='c_uname']"));
        email_id.sendKeys("hi");
        Thread.sleep(5000);

        driver.close();
        driver.quit();
    }  
}

smottt · Accepted Answer · 2015-01-31 07:36:40Z

5

You can handle popup window or alert box:

Alert alert = driver.switchTo().alert();
alert.accept();

You can also decline the alert box:

Alert alert = driver.switchTo().alert();
alert().dismiss();

edited Jan 31, 2015 at 7:36

smottt

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answered Jan 31, 2015 at 7:24

ER.swatantra

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Comments

Sandeep · Accepted Answer · 2016-05-16 06:30:24Z

5

You can use the below code inside your code when you get any web browser pop-up alert message box.

// Accepts (Click on OK) Chrome Alert Browser for RESET button.

Alert alertOK = driver.switchTo().alert();
alertOK.accept();



//Rejects (Click on Cancel) Chrome Browser Alert for RESET button.

Alert alertCancel = driver.switchTo().alert();
alertCancel.dismiss();

edited May 16, 2016 at 6:30

Sandeep

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answered Mar 25, 2016 at 9:47

Manasis Mishra

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1 Comment

Manasis Mishra Over a year ago

You can use the above code inside your code when you get any web browser pop up alert message box.

alecxe · Accepted Answer · 2014-10-01 15:22:16Z

2

Do not make the situation complex. Use ID if they are available.

driver.get("http://www.rediff.com");
WebElement sign = driver.findElement(By.linkText("Sign in"));
sign.click();
WebElement email_id= driver.findElement(By.id("c_uname"));
email_id.sendKeys("hi");

edited Oct 1, 2014 at 15:22

alecxe

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answered Oct 16, 2013 at 13:11

HemChe

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6 Comments

Niyati Over a year ago

I can''t directly use email_id field as its in pop up window ..pls visit rediff.com as i want to write email address and password in sign in form of rediff.com. link: rediff.com

HemChe Over a year ago

which browser are you using? Because i am not seeing any pop up window after clicking on sign-in. it is just another modal window (inside main window). i am using firefox23.

Niyati Over a year ago

yeh i need to access that and signed in

HemChe Over a year ago

what is error you are getting while clicking on sign-in link? Any permission error?

Niyati Over a year ago

didn't get any error but not able to handle email address field

|

Sandip · Accepted Answer · 2015-07-28 08:58:06Z

0

When the toastr message poped up on the screen of firefox. the below tag was displayed in fire bug.

<div class="toast-message">Invalid Credentials, Please check Password</div>.

I took the screenshot at that time. And did the below changes in selenium java code.

String alertText = "";
WebDriverWait wait = new WebDriverWait(driver, 5);
wait.until(ExpectedConditions.visibilityOfElementLocated(By.className("toast-message")));
WebElement toast1 = driver.findElement(By.className("toast-message"));  
alertText = toast1.getText();
System.out.println( alertText);

And my issue of toastr popup got resolved.

answered Jul 28, 2015 at 8:58

Sandip

1

Comments

Machavity · Accepted Answer · 2018-11-17 03:02:42Z

0

String parentWindowHandler = driver.getWindowHandle(); // Store your parent window
String subWindowHandler = null;

Set<String> handles = driver.getWindowHandles(); // get all window handles
Iterator<String> iterator = handles.iterator();

subWindowHandler = iterator.next();

driver.switchTo().window(subWindowHandler); // switch to popup window

// Now you are in the popup window, perform necessary actions here

driver.switchTo().window(parentWindowHandler);  // switch back to parent window

edited Nov 17, 2018 at 3:02

Machavity♦

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answered Nov 17, 2018 at 3:00

user3150673

1

Comments

Greg Harward · Accepted Answer · 2023-09-20 13:31:30Z

0

It isn't Java, but if the comparison helps, here is a simple Python solution in Chrome that handles the question in a single line.

from selenium import webdriver

driver = webdriver.Chrome()
driver.get(url)

# Save a list of all open window handles
window_handles = driver.window_handles

# Open new window with click() action - modify as needed.
get_element(driver, By.XPATH, "//input[@title]").click()

# Get and switch to the pop-up window
new_popup_window = list(set(driver.window_handles) - set(window_handles))[0]
driver.switch_to.window(new_popup_window)

edited Sep 20, 2023 at 13:31

answered Sep 16, 2023 at 17:59

Greg Harward

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1 Comment

Community Over a year ago

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Satheesh kumar · Accepted Answer · 2014-11-20 11:46:06Z

-1

       //get the main handle and remove it
       //whatever remains is the child pop up window handle

       String mainHandle = driver.getWindowHandle();
       Set<String> allHandles = driver.getWindowHandles();
       Iterator<String> iter = allHandles.iterator();
       allHandles.remove(mainHandle);
       String childHandle=iter.next();

answered Nov 20, 2014 at 11:46

Satheesh kumar

492 bronze badges

Comments

Shahzad Barkati · Accepted Answer · 2015-12-16 07:46:21Z

-1

public void Test(){

     WebElement sign = fc.findElement(By.xpath(".//*[@id='login-scroll']/a"));
        sign.click();
        WebElement LoginAsGuest=fc.findElement(By.xpath(".//*[@id='guest-login-option']"));
        LoginAsGuest.click();
        WebElement email_id= fc.findElement(By.xpath(".//*[@id='guestemail']"));
        email_id.sendKeys("[email protected]");
        WebElement ContinueButton=fc.findElement(By.xpath(".//*[@id='contibutton']"));
        ContinueButton.click();

}

edited Dec 16, 2015 at 7:46

Shahzad Barkati

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answered Dec 16, 2015 at 7:41

ankush deol

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