jQuery Dynamic Function and Variable

Question

I am trying to create a function that handles the 'keyup' event for several input fields and passes the input value to a php script. Here's the code I have so far

$(document).ready(function () {

    $("#email").keyup(function () {

        val = $("input#email").val();
        what = 'email';

        aFunction(val, what);

    });

});

function aFunction(val, what) {

    var dataString = what + '=' + val;
    var error = "email_check";

    $.post("key.php", dataString, function (data) {
        //if (data.[error] == 'invalid'){
        if (data.email_check == 'invalid') {
            $("#ppp").html('error');
        } else {
            $("#ppp").html('good to go');
        }
    }, "json");

    //return false; 
}

When I uncomment

//if (data.[error] == 'invalid'){

and comment out

if (data.email_check == 'invalid'){

My the script doesnt execute and js file doesn't load into the firebug script console - I assume means there's an error because when I undo that and refresh I can view it. I've tried added single and double quotes to the variable. Also, it would be helpful if there was a way to see what the is error is, but I don't know how to do that.

Mods - why do you keep editing my posts? Am I doing something wrong, I cant see any changes? — Joe Riggs
– Joe Riggs, Commented Dec 21, 2009 at 16:16
I added the javascript tag to the question, as I saw the problem was just a syntax error. Is that ok? — Crescent Fresh
– Crescent Fresh, Commented Dec 21, 2009 at 17:07
No problem at all, I just thought I was making more work for you guys :) — Joe Riggs
– Joe Riggs, Commented Dec 21, 2009 at 18:19

Jacob Mattison · Accepted Answer · 2009-12-21 16:07:34Z

2

Your primary problem here is that you should use either dot notation ("data.error") or array notation ("data['error']") but not both ("data.['error']").

answered Dec 21, 2009 at 16:07

Jacob Mattison

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2 Comments

kangax Over a year ago

It's actually called "bracket notation" ;)

Joe Riggs Over a year ago

ps - what's my secondary problem?

SLaks · Accepted Answer · 2009-12-21 16:08:45Z

1

Javascript does not support braces in identifiers.

If the key is actually just error, you can write if (data.error == 'invalid').
If it is [error], you'll need to write if (data['[error]'] == 'invalid)`.

To see syntax errors, go to Firebug's Console tab.

answered Dec 21, 2009 at 16:08

SLaks

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1 Comment

Joe Riggs Over a year ago

+1 thanks for the heads up on console tab. I kept googling for 'validate jquery code' and it came back with links for the validator plugin

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