I am wondering if there is a 'smart' way (one regex expression) to extract IDs from the following paragraph:
...
imgList = '9/optimized/1260089_fpx.tif,0/optimized/1260090_fpx.tif';
...
The result shoul be a list containing 1260089 and 1260090. The count of the IDs might be up to 10.
I need something like:
re.findall('imgList = (some expression)', string)
Any ideas?
Best would be to use a single regex finding all the numbers. I call for re.findall
>>> imgList = '9/optimized/1260089_fpx.tif,0/optimized/1260090_fpx.tif'
>>> import re
>>> re.findall('optimized/([0-9]*)_fpx', imgList)
['1260089', '1260090']
You could of course make the regex stronger, but if the data is as you indicated, this should suffice.
import re
s = '9/optimized/1260089_fpx.tif,0/optimized/1260090_fpx.tif'
print(re.findall(r'(\d+)_fpx.tif', s))
If the optimzed/ an _fpx part is not ensured and the ID is between 7 and 10 digits
you could do something like
import re
re.findall('[\d]{7,10}', imgList)
This will find a 7 to 10 digit number in the string, hence, IDs with 0-6 or more than 10 digits will be excluded.
import re
imgList = '9/optimized/1260089_fpx.tif,0/optimized/1260090_fpx.tif'
re.findall(r'([0-9]){7}',imgList)
['1260089', '1260090']
The code can only meet your situation.
