Given a function's name (as a string), can I get that function's parameter list (assuming it exists in the same file)? Basically, here's what I want:
def foo(bar):
print str(bar);
funcName = 'foo';
printFunctionParameters(funcName);
where I obviously want printFunctionParameters to print bar.
Any suggestions?
Use the inspect module:
>>> import inspect
>>> def foo(bar):pass
>>> inspect.getargspec(foo)
ArgSpec(args=['bar'], varargs=None, keywords=None, defaults=None)
a = 'foo', then all I have to do is use the eval function along with your suggestion, i.e. inspect.getargspec(eval(a)). Please update your answer so that I can set it as correct. Thanks.
__dict__. Use inspect.getargspec(module.__dict__[funcName]) or inspect.getargspec(globals()[funcName]) depending on whether the function is in the current module or not.eval?In Python 3, inspect.getargspec() is deprecated, and you should use inspect.signature()
import inspect
inspect.signature(foo)
Try either,
import inspect
def foo(bar):pass
inspect.getargspec(eval('foo'))
or,
import inspect
import __main__
def foo(bar):pass
inspect.getargspec(__main__.__getattribute__('foo'))
