regex basic url expression

Question

Hi I'm creating a regular expression (ruby) to test the beginning and end of string. I have both parts but can't join them.

Beginning of string

\A(http:\/\/+)

End of string

(.pdf)\z

How to join? Bonus if it could validate in-between and accept anything (to avoid http://.pdf)

By the way, rubular http://rubular.com is a neat place to validate expressions

User 12345678 · Accepted Answer · 2013-11-12 12:59:44Z

1

Use .+ to match any character except \n one or more times.

\A(http:\/\/+).+(\.pdf)\z

Should match http://www.stackoverflow.com/bestbook.pdf but not http://.pdf

edited Nov 12, 2013 at 12:59

answered Oct 19, 2013 at 20:50

User 12345678

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2 Comments

trh Over a year ago

this is a good option if you're sure it's always all or nothing. it won't match http://.pdf but it will match http://foo.pdfor even http:///.pdf basically as long as there is at least one character between the / and the . it will still pass.

pguardiario Over a year ago

I'm pretty sure you meant to escape the . in .pdf. Also, the grouping is unnecessary as well as the + after \/\/. No -1 though because I'm feeling generous.

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