passing php object into array/list like in java

Question

maybe its duplicate but i cant find it.

    something = new ArrayList<>(); 
something.add(new Object("Hello"));
something.add(new object("World"));
something.add(new Object("!"));
for(blablabla){
System.out.print(something.get(i).getTextFromConstructor());
}

this will print "Hello World!"

in php i dont know solution to pass whole objects into array to call their methods from loop or just by something[0]->method(); As i know this in php cannnot be done, but maybe i am wrong :-)

Thank You

goat · Accepted Answer · 2013-10-21 04:27:01Z

1

$arr = array();
$arr[] = new MyUSerDefinedObject("Hello");
//...

echo $arr[0]->methd();
//or
foreach ($arr as $val) {
    echo $val->methd();
}

answered Oct 21, 2013 at 4:27

goat

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3 Comments

Erik Kubica Over a year ago

lol it works? i tried it few years before but it does not worked. Thanks

Erik Kubica Over a year ago

ohh, with for it does not worked but with foreach yes.. thankyou

Erik Kubica Over a year ago

now i feel like begginer :D. Now i can write more object oriented php code

Amy Degregorio · Accepted Answer · 2013-10-21 04:28:02Z

0

Use this example to set the bridge b/w php and java so that you can pass values to them

<?php
$date = new Java("java.util.Date", 70, 9, 4);
var_dump($date->toString());
$map = new Java("java.util.HashMap");
$map->put("title", "Java Bridge!");
$map->put("when", $date);
echo $map->get("when")->toString()."\n";
echo $map->get("title")."\n";

$array = array(1,2,3,4,5);
$map->put("stuff", $array);
var_dump($map->get("stuff"))."\n";

$system = new JavaClass("java.lang.System");
echo "OS: ".$system->getProperty("os.name")."\n";
$math = new JavaClass("java.lang.Math");
echo "PI: ".$math->PI."\n";
?>

answered Oct 21, 2013 at 4:28

Amy Degregorio

1

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