I want to get the index of First ever character appear in the string.
for example : I have a string " 225 get first character " In this I want the index of 'g' .how to get this ?
thanks
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1Have you ever taken a look at RegExpressions?Reporter– Reporter2013-10-21 08:23:57 +00:00Commented Oct 21, 2013 at 8:23
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@reporter ..Can you help me out with this one ?Rajeev– Rajeev2013-10-21 08:26:37 +00:00Commented Oct 21, 2013 at 8:26
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4 Answers
var str = " 225 get first character ";
var index = /[a-z]/i.exec(str).index;
alert(index); // 5
3 Comments
Rajeev
it will return 4..anyways it helped me :)
Sebastien C.
It returns 5 on latest Firefox.
Alex
This is a regex literal case insensitive
/i search for English letters, returning a zero based index of the match in string. Very nice!You may use a regular expression:
var str = " 225 get first character ";
var firstChar = str.match('[a-zA-Z]');
//'g'
And if you want the index,
var index = str.indexOf(firstChar);
Comments
I have simplified @Jorgeblom answer:
var str = " 255 get first character";
var firstCharIndex = str.match('[a-zA-Z]').index;
console.log(firstCharIndex);
// 6
The match() function return a array with following values:
- [0] - First matching character => "g"
- [index] - Index of the first match => 6
- [input] - the whole input string
- [groups] - empty in these case. If you declare grouped regex conditions, these groups will be listed here with the matching results
Comments
you can use
var str = " 225 get first character ";
var first_char = str.search(/[a-zA-Z]/);
