I tried:
from time import sleep
while sleep(3):
input("Press enter to continue.")
But it doesn't seem to work. I want the program to await user input, but if there's no user input after 10 minutes, continue with the program anyway.
This is with python 3.
Why does the code not work?
time.sleep returns nothing; the value of the time.sleep(..) become None; while loop body is not executed.
How to solve it
If you're on Unix, you can use select.select.
import select
import sys
print('Press enter to continue.', end='', flush=True)
r, w, x = select.select([sys.stdin], [], [], 600)
Otherwise, you should use thread.
Windows specific solution that use msvcrt:
import msvcrt
import time
t0 = time.time()
while time.time() - t0 < 600:
if msvcrt.kbhit():
if msvcrt.getch() == '\r': # not '\n'
break
time.sleep(0.1)
Here is a simple way using an alarm. When the time expires, the lambda function is called, which would raise a ZeroDivisionError.
from signal import signal, alarm, SIGALRM
signal(SIGALRM, lambda x, y: 1/0)
try:
alarm(600)
input("Press enter to continue.")
except ZeroDivisionError:
print("timed out")
signal.alarm is only available in Unix.
Another way to do it is this:
from time import sleep
print("I'm executing")
try:
print("Wake up Ctrl-C!")
sleep(600)
except KeyboardInterrupt:
print("I woke up!")
else:
print("I'm executing again.")
Not the greatest of answers and it definitely feels like an abuse of exceptions, but it works.
