php loop by date of the month

Question

Provided the code stated below, the output are (see below). My question is why after 2009/11/01 it follow's by 2009/11/30 and 2009/12/30 instead of 2009/12/01. From 2009/06/01 ~ 2009/11/01 there is no problem.

output
2009/06/01
2009/07/01
2009/08/01
2009/09/01
2009/10/01
2009/11/01
2009/11/30
2009/12/30

my code

<?php

$startdate = "2009/06/01";
$enddate = "2009/12/31";

$start = strtotime($startdate); 
$end = strtotime($enddate); 

$currentdate = $start; 
while($currentdate < $end)
{
    $cur_date = date('Y/m/d',$currentdate);
    $month = date('m', $currentdate); 
    $year = date('Y', $currentdate); 
    $monthLength = daysOfMonth($month, $year); 
    $currentdate += $monthLength; 

    echo $cur_date . "<br />";  
}


function daysOfMonth($month, $year)
{
    return (86400 * date("t", strtotime($year."-".$month."-01")));
} 

?>

is Alvaro's answer adequate? You should either mark it as Accepted or comment on what's wrong still. — philfreo
– philfreo, Commented Dec 26, 2009 at 4:37

Álvaro González · Accepted Answer · 2009-12-23 08:07:43Z

1

<?php

$startdate = "2009/06/01";
$enddate = "2009/12/31";

$start = strtotime($startdate);
$end = strtotime($enddate);

$currentdate = $start;
while($currentdate < $end)
{
        $cur_date = date('Y/m/d', $currentdate);

        $currentdate = strtotime('+1 month', $currentdate);

        echo $cur_date . "<br />";
}

?>

answered Dec 23, 2009 at 8:07

Álvaro González

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2 Comments

tirso Over a year ago

hi alvaro, sorry for my late replied, due to Christmas holiday I wasn't able to work and read your answer. BTW, your code works perfectly, how about if the start date not started with day 01, let say $startdate = "2009/06/06" ? Thank you very much

Álvaro González Over a year ago

Is it a new question? Once you have a Unix timestamp, you have a great choice of functions to manipulate it. You can extract fragments with date() and generate new timestamps with mktime().

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