Is there something similar to DATEFROMPARTS(year, month, day) in SQL Server 2008? I want to create a date using the current year and month, but my own day of the month. This needs to be done in one line in order to be used in a computed column formula.
For Example (I'm not sure if it works because I do not have SQL Server 2012):
DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), 3)
Is there a way to do this in SQL Server 2008?
DATEFROMPARTS Seems only available in SQL Server 2012 (link)
Using the 3 from your example, you could do this:
dateadd(dd, 3 -1, dateadd(mm, datediff(mm,0, current_timestamp), 0))
It works by finding the number of months since the epoch date, adding those months back to the epoch date, and then adding the desired number of days to that prior result. It sounds complicated, but it's built on what was the canonical way to truncate dates prior to the Date (not DateTime) type added to Sql Server 2008.
You're probably going to see other answers here suggesting building date strings. I urge you to avoid suggestions to use strings. Using strings is likely to be much slower, and there are some potential pitfalls with alternative date collations/formats.
Msg 102, Level 15, State 1, Line 1 Incorrect syntax near 'dd'.select in front of what's there now and paste it directly into a query window in Management Studio, I get 2013-10-03 00:00:00.000 if I run it right now.SELECT. This is exactly what I am looking for.You could use something like this to make your own datetime:
DECLARE @year INT = 2012
DECLARE @month INT = 12
DECLARE @day INT = 25
SELECT CAST(CONVERT(VARCHAR, @year) + '-' + CONVERT(VARCHAR, @month) + '-' + CONVERT(VARCHAR, @day)
AS DATETIME)
CREATE FUNCTION DATEFROMPARTS
(
@year int,
@month int,
@day int
)
RETURNS datetime
AS
BEGIN
declare @d datetime
select @d = CAST(CONVERT(VARCHAR, @year) + '-' + CONVERT(VARCHAR, @month) + '-' + CONVERT(VARCHAR, @day) AS DATETIME)
RETURN @d
END
GO
Based in Joel and Alejandro's answer, I would suggest this user function
CREATE FUNCTION MyDATEFROMPARTS
(
@year int,
@month int,
@day int
)
RETURNS datetime
AS
BEGIN
RETURN select @d = dateadd(dd,@day-1,dateadd(mm,@month-1, dateadd(yyyy,@year-1900, 0)))
END;
Explaning the trick : in SQL Server, date 0 is 1/1/1900, so the first dateadd ( dateadd(yyyy,@year-1900, 0) ) results in the first day of the year you want, after that you add the month quantity : dateadd(mm,@month-1, ... At last, you add the number of days.
To use a user function remember to add the schema :
select dbo.MyDATEFROMPARTS(1854,8,3)
You can also extend the function adding hours, minutes and seconds :-)
CREATE FUNCTION DATEFROMPARTS
(
@year int,
@month int,
@day int
)
RETURNS datetime
AS
BEGIN
declare
@sy varchar(max)
,@sm varchar(max)
,@sd varchar(max)
;
set @sy = convert(varchar(max),@year);
set @sm = (case when @month<10 then '0' else '' end) +
convert(varchar(max),@month);
set @sd = (case when @day<10 then '0' else '' end) +
convert(varchar(max),@day);
RETURN convert(datetime, @sy + '-' + @sm + '-' + @sd + 'T00:00:00.000');
END
International Coding - YYYY-DD-MM and YYYY-MM-DD is supported
select @d = convert(datetime, CONVERT(VARCHAR, @year)
+ '-' + CONVERT(VARCHAR, @month) + '-' + CONVERT(VARCHAR, @day),102)
RETURN @d
