Open images from a folder one by one using python?

Question

Hi all I need to open images from a folder one by one do some processing on images and save them back to other folder. I am doing this using following sample code.

path1 = path of folder of images    
path2 = path of folder to save images    

listing = os.listdir(path1)    
for file in listing:
    im = Image.open(path1 + file)    
    im.resize((50,50))                % need to do some more processing here             
    im.save(path2 + file, "JPEG")

Is there any best way to do this?

Thanks!

It seems ok with processing one after another, avoiding the load to memory. — Siva Cn
– Siva Cn, Commented Oct 24, 2013 at 18:33
Just FYI, the Python comment character is #, not % (LaTeX programmer?). That might save you some trouble in the future. :) — Christian Ternus
– Christian Ternus, Commented Oct 24, 2013 at 18:35
What are you actually trying to do? Please put a little more description in your question -- help us help you by making your question as complete as possible. — Christian Ternus
– Christian Ternus, Commented Oct 24, 2013 at 18:36
If you want it to not be a blocking call, I would create a thread for every image processing. — jramirez
– jramirez, Commented Oct 24, 2013 at 18:36
@ChristianTernus: As I mention above, I need to open images from one folder and by doing some processing need to save them in another folder. At present I am doing this by opening one image at a time, process it and then saving it into another folder. My question is whether it can be done for all images at a time rather than opening them one by one? — user2766019
– user2766019, Commented Oct 24, 2013 at 20:00

richar8086 · Accepted Answer · 2014-10-14 16:04:24Z

13

Sounds like you want multithreading. Here's a quick rev that'll do that.

from multiprocessing import Pool
import os

path1 = "some/path"
path2 = "some/other/path"

listing = os.listdir(path1)    

p = Pool(5) # process 5 images simultaneously

def process_fpath(path):
    im = Image.open(path1 + path)    
    im.resize((50,50))                # need to do some more processing here             
    im.save(os.path.join(path2,path), "JPEG")

p.map(process_fpath, listing)

(edit: use multiprocessing instead of Thread, see that doc for more examples and information)

edited Oct 14, 2014 at 16:04

richar8086

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answered Oct 24, 2013 at 20:04

Christian Ternus

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Comments

Pankaj Bokdia · Accepted Answer · 2017-07-24 15:15:44Z

2

You can use glob to read the images one by one

import glob
from PIL import Image


images=glob.glob("*.jpg")
for image in images:
    img = Image.open(image)
    img1 = img.resize(50,50)
    img1.save("newfolder\\"+image)

answered Jul 24, 2017 at 15:15

Pankaj Bokdia

211 bronze badge

1 Comment

Casey L Over a year ago

This is good, but correct syntax is img.resize((50,50)) with the (50,50) as a tuple. Otherwise the second 50 gets interpreted as the resample argument and you'll get PIL: ValueError: unknown resampling filter

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