Match Url path without query string

Question

I would like to match a path in a Url, but ignoring the querystring. The regex should include an optional trailing slash before the querystring.

Example urls that should give a valid match:

/path/?a=123&b=123

/path?a=123&b=123

So the string '/path' should match either of the above urls.

I have tried the following regex: (/path[^?]+).*

But this will only match urls like the first example above: /path/?a=123&b=123

Any idea how i would go about getting it to match the second example without the trailing slash as well?

Regex is a requirement.

(/path[?]+|/path/[?]+).*

keenthinker
– keenthinker

2013-10-27 21:40:53 +00:00
Commented Oct 27, 2013 at 21:40 — keenthinker
– keenthinker, Commented Oct 27, 2013 at 21:40

freakish · Accepted Answer · 2013-10-27 22:03:55Z

9

No need for regexp:

url.split("?")[0];

If you really need it, then try this:

\/path\?*.*

EDIT Actually the most precise regexp should be:

^(\/path)(\/?\?{0}|\/?\?{1}.*)$

because you want to match either /path or /path/ or /path?something or /path/?something and nothing else. Note that ? means "at most one" while \? means a question mark.

BTW: What kind of routing library does not handle query strings?? I suggest using something else.

edited Oct 27, 2013 at 22:03

answered Oct 27, 2013 at 21:28

freakish

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3 Comments

JCoder23 Over a year ago

I should have noted that i am required to use regex. I am using a routing library that uses regex to match urls.

freakish Over a year ago

@JCoder23 Updated one more time

JCoder23 Over a year ago

Im using CasperJS with the PhantomJS webserver module. The web server module is a basic http server (Mongoose), which does not have routing built in. I found a routing library someone wrote for it, that does not support query strings, as in urls will not match if a querystring is appended to the url. So i needed this regex to match a route without the query string, i then patched the routing library to correctly parse out the query string and add it to the request object of the route.

Kevin Collins · Accepted Answer · 2013-10-27 21:45:22Z

4

http://jsfiddle.net/bJcX3/

var re = /(\/?[^?]*?)\?.*/;

var p1 = "/path/to/something/?a=123&b=123";
var p2 = "/path/to/something/else?a=123&b=123";

var p1_matches = p1.match(re);
var p2_matches = p2.match(re);

document.write(p1_matches[1] + "<br>");
document.write(p2_matches[1] + "<br>");

answered Oct 27, 2013 at 21:45

Kevin Collins

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