Extract Data from XML in Java

Question

I have this xml data format. I would like to extract the properties name and value from it. I have tried to get node by node but it is troublesome.

<?xml version="1.0"> encoding="ASCII"?> 
<xDiagram>  
  <children iD="1261435145010.0" location="Point(547,184)" 
    size="Dimension(102,140)" shapeType="TestInfoShape"
    modelEntityID="TestInfo.7">
    <properties>
      <properties name="desc" type="MultiLinesText"
        parent="this_comp1" parentName="multiLinesText"
        modelPropName="desc" value="create test user can access"/>
      <properties name="name" type="String" parent="this_comp2"
        parentName="text" modelPropName="name" value="testCase1"/>
    </properties>
  </children>
</xDiagram>

Can anyone suggest a better way to do it? I like to use XPath but it can't lock on the element.

Thanks

did some editing, hardly enough, but data is shown now.

Tom
– Tom

2009-12-28 04:12:24 +00:00
Commented Dec 28, 2009 at 4:12 — Tom
– Tom, Commented Dec 28, 2009 at 4:12
This XML is invalid. Copy'n'paste bug? Or also in real?

BalusC
– BalusC

2009-12-28 04:31:56 +00:00
Commented Dec 28, 2009 at 4:31 — BalusC
– BalusC, Commented Dec 28, 2009 at 4:31

Mark Renouf · Accepted Answer · 2009-12-28 04:23:20Z

3

XPath is the right tool for this type of job. You can try improving your XPath expression at a site like:

http://www.whitebeam.org/library/guide/TechNotes/xpathtestbed.rhtm

For example, this XPath will return a NodeList containing all of the inner "Properties" elements:

/xDiagram/children/properties/properties

answered Dec 28, 2009 at 4:23

Mark Renouf

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Jeremy Raymond · Accepted Answer · 2009-12-28 04:56:13Z

0

The Java Streaming API for XML is also handy (when SAX, DOM, or XPath aren't quite right for the job).

answered Dec 28, 2009 at 4:56

Jeremy Raymond

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Ravi Gupta · Accepted Answer · 2009-12-28 07:22:09Z

0

See if JAXB helps you: http://www.roseindia.net/jaxb/r/jaxb.shtml

answered Dec 28, 2009 at 7:22

Ravi Gupta

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