PHP count the amount of not empty values of array

Question

I have this array:

$auflistung = array ($_POST['jacken'], $_POST['hosen'], $_POST['oberteil'], $_POST['tasche'], $_POST['schuhe'], $_POST['accessoireschmuck1'], $_POST['accessoireschmuck2'], $_POST['accessoireschmuck3'], $_POST['accessoireschmuck4'], $_POST['accessoireschmuck5'], $_POST['accessoireschmuck6']);

It contains e.g.:

array(11) {
  [0]=>      string(10) "1288023365"
  [1]=>      string(10) "1246154493"
  [2]=>      string(0) ""
  [3]=>      string(10) "1293143681"
  [4]=>      string(10) "1293143242"
  [5]=>      string(0) ""
  [6]=>      string(0) ""
  [7]=>      string(0) ""
  [8]=>      string(0) ""
  [9]=>      string(0) ""
  [10]=>     string(0) ""
}

Now i need the amount of aviable values. In this case 4

I tried: echo count( $auflistung ); but the result includes allso the empty values, so 11. Any ideas?

Why not fix the origin of the empty elements and create the array with only non empty values? — CodeZombie
– CodeZombie, Commented Oct 31, 2013 at 0:25

Popnoodles · Accepted Answer · 2013-10-31 00:34:09Z

4

Use array_filter to iterate over each value. If you don't provide a callback, any key whose value == false gets removed. Empty is close enough to false for PHP.

echo count(array_filter($auflistung));

ZombieHunter has a good point about creating the array from non-empty values. This is a clean way of doing that.

$keys=array(
    'jacken', 
    'hosen', 
    'oberteil', 
    'tasche', 
    'schuhe', 
    'accessoireschmuck1', 
    'accessoireschmuck2', 
    'accessoireschmuck3', 
    'accessoireschmuck4', 
    'accessoireschmuck5', 
);

$auflistung=array();
foreach ($keys as $key){
    if (isset($_POST[$key]) && !empty($_POST[$key])) $auflistung[]=$_POST[$key];
}

echo count($auflistung);

edited Oct 31, 2013 at 0:34

answered Oct 31, 2013 at 0:25

Popnoodles

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