for (i = 1; i <= 6; i++) {
$.post("ajax.php", {param: i}, function (response) {
console.log(i);
});
}
How to get correct i variable in $.post complete function, Can I pass variable to it?
-
Here is How to Answer[1] to your question - use factory function. [1]: stackoverflow.com/questions/10171106/…yAnTar– yAnTar2013-10-31 08:47:31 +00:00Commented Oct 31, 2013 at 8:47
-
How do JavaScript closures work?Andreas– Andreas2013-10-31 08:55:02 +00:00Commented Oct 31, 2013 at 8:55
Add a comment
|
1 Answer
Add an IIFE to it, this will copy the outer i for each instance:
for (i = 1; i <= 6; i++) {
!function( i ){
$.post("ajax.php", {param: i}, function (response) {
console.log(i);
});
}( i );
}
Edit
As for the question in the comments:
In the above code I use the ! to tell the parser, that there is a function expression to follow and not a function declaration. This is needed in order to have a IIFE, but you can use a whole lot of different ways to do so as mentioned by @Wayne.
For more details, have a look at this question:
8 Comments
lastr2d2
Besides
!, + - ~ would do the same job
Sina R.
@Sirko - can you explain more? what is
! for?Sina R.
if your code works it is a perfect code. How is my code? longer but I think true.
Sirko
@imsiso You have to tell the parse somehow, that this is a function expression and not a declaration (see, e.g., this question). In my answer I used a
! to do so. In general there are plenty of ways to do this.Sina R.
@Sirko - would
! be same as using var tmp=functio...? and why i is still known in the ajax callback? |