Appending PHP variable in javascript url

Question

I have the following

$id=$this->uri->segment(3);

I want to pass the variable data through a javascript url and I did it the following way :

<script>
$(document).ready(function(){
        setInterval(function() {
            $.ajax({
                type: "GET",                   
                url: "<?php echo base_url(); ?>pharm_profile/prescriptions/<?php $id; ?>",
                dataType: "JSON",
                success: function(prescription) {               
                    prescription_list=$('#prescription_list').empty();                        
                    $.each(prescription, function(i, prescription){                          
                       prescription_list.append('<div style="color: white;"><a style="color: white;" href="<?php echo base_url(); ?>pharm_profile/dispense_details/'+prescription.id+'">'+prescription.medname+'</a></a>\n\
            </br></div>');                        
                       // prescription_list.append('<li span="font_color:white !important;"><a href="<?php //echo base_url(); ?>transactions/details/'+prescription.medname+'">'+prescription.medname+'</a></li></a></br>');            
                    });
                },
                error: function(data) {
                    //alert(data);
                }
            });
        });


    });
</script>

When I run the script I only get url up to prescription leaving out the id. What is the best way to include the id?

웃웃웃웃웃 · Accepted Answer · 2013-10-31 10:03:21Z

1

You forget to add echo before the variable

Change the url or four ajax

url: "<?php echo base_url(); ?>pharm_profile/prescriptions/<?php $id; ?>",

to this

url: "<?php echo base_url(); ?>pharm_profile/prescriptions/<?php echo $id; ?>",

answered Oct 31, 2013 at 10:03

웃웃웃웃웃

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Comments

Rohan Kumar · Accepted Answer · 2013-10-31 10:03:54Z

1

Use echo to set the value $id,

url: "<?php echo base_url(); ?>pharm_profile/prescriptions/<?php echo $id; ?>",

answered Oct 31, 2013 at 10:03

Rohan Kumar

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Comments

Legionar · Accepted Answer · 2013-10-31 10:03:32Z

0

Change this line, you are missing echo:

url: "<?php echo base_url(); ?>pharm_profile/prescriptions/<?php echo $id; ?>",

answered Oct 31, 2013 at 10:03

Legionar

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