Check if one of multiple values exists in array as a partial string match

Question

For array with single values like

array(2) {
  ["blue"]=>
  int(0)
  ["red"]=>
  int(1)
}

I use this code

<?php
if (array_key_exists('blue',$array))
{
    echo "jo";
}
?>

But what code do I need to use for arrays like this

array(2) {
  ["yellow blue"]=>
  int(0)
  ["red white"]=>
  int(1)
}

to check if blue exists?

yes, check for 'yellow blue' works but not the check for blue only — Matthias Müller
– Matthias Müller, Commented Nov 3, 2013 at 0:07

AbraCadaver · Accepted Answer · 2013-11-03 00:37:02Z

2

My take:

if(preg_grep('/blue/', array_keys($array))) { echo 'found'; }

Or if you want to get them:

$matches = preg_grep('/blue/', array_keys($array));
print_r($matches);

edited Nov 3, 2013 at 0:37

answered Nov 3, 2013 at 0:23

AbraCadaver

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5 Comments

AbraCadaver Over a year ago

I saw other comments, you have to adjust the pattern if you don't want greenblue etc. You have to be specific about what you want.

Matthias Müller Over a year ago

your second code works but the first one looks better but the page isn't loading with it, is there may be an error in the code?

AbraCadaver Over a year ago

Yes, edited. But these are examples not copy paste for you. Does your editor not have some syntax highlighting?

Matthias Müller Over a year ago

No, which editor would you recommand? Your code works great :D

AbraCadaver Over a year ago

Depends. If you're serious about coding projects then check out an IDE (eclipse, netbeans, aptana, scores of others). Notepad++ is a good text editor for windows that has syntax highlighting. Not sure about Mac, but I use Linux and most if not all editors have some mode for programming of popular languages.

KingCrunch · Accepted Answer · 2013-11-03 00:11:56Z

2

$partialKey = 'blue';
$byPartialKey = function ($key) use ($partialKey) {
    $parts = explode(' ', $key);
    return in_array($partialKey, $parts);
};

$result = array_filter (array_keys($input), $byPartialKey);

$result now contains all keys, that somehow contains $partialKey.

answered Nov 3, 2013 at 0:11

KingCrunch

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3 Comments

Matthias Müller Over a year ago

Thanks but how do I echo something if blue is found?

Matthias Müller Over a year ago

If $result if empty then echo "is there" or else "not there" right?

KingCrunch Over a year ago

@MatthiasMüller With echo. Actually I don't know, whats the matter now. --- echo $result ? 'one or more "blue" found' : 'No "blue" found';

Emilio Gort · Accepted Answer · 2013-11-03 00:40:14Z

2

you can do using regular expression

search='blue';
foreach ($array as $key => $value) {
 if (preg_match('~'.$search.'~i',$key)) {
    echo "jo";
 }
}

The \b in the pattern indicates a word boundary, so only the distinct word "blue" is matched, and not a word partial like "bluegreen"

search='blue';
foreach ($array as $key => $value) {
 if (preg_match('/\b'.$search.'\b/i',$key)) {
    echo "jo";
 }
}

Reference

edited Nov 3, 2013 at 0:40

answered Nov 3, 2013 at 0:12

Emilio Gort

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6 Comments

KingCrunch Over a year ago

Thought of this too, but this also hits for example yellow bluegreen. Don't know, if this is an issue now, but changing requirements can make that an issue later, so I wouldn't rely on it.

Emilio Gort Over a year ago

You have to define the regular expression you want, only the word blue, o that contain blue in the string

Matthias Müller Over a year ago

I tried $search='blue'; foreach ($myarray as $key => $value) { if (preg_match('/\b'.$search.'\b/i',$key) { echo "jo"; } } but the page isn't loading

Emilio Gort Over a year ago

It was missing a close parenthesis in the IF, answer updated

Matthias Müller Over a year ago

Now it works too and is great for exact match. But for now i don't need exact match so I accepted AbraCadaver's solution

|

Langusten Gustel · Accepted Answer · 2013-11-03 00:24:24Z

0

I would do it like this:

function subkey_exists($string, $array) {
    foreach($array as $key => $value) {
        $sub_keys = explode(" ", $key);
        if(in_array($string,$sub_keys)) {
            return true;
        }
    }
    return false;
}

[edit]

updated to your requirements

edited Nov 3, 2013 at 0:24

answered Nov 3, 2013 at 0:15

Langusten Gustel

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1 Comment

KingCrunch Over a year ago

See my commet at Emilios answer: This also covers yell bluegreen

OneOfOne · Accepted Answer · 2013-11-03 00:28:54Z

0

Yet another array_filter solution :

<?php
function find_keys_like($key, $array) {
    return array_filter(array_keys($array), function($k) use (&$key) {
        return strpos($k, $key) > -1;
    });
}
function array_has_key_like($key, $array) {
    return count(find_keys_like($key, $array)) > 0;
}

//test
$a = array('blue' => 1, 'yellow blue' => 2, 'green' => 3);
print_r(find_keys_like('blue', $a));
echo 'blue exists ? ' . (array_has_key_like('blue', $a) ? 'yes' : 'no') . PHP_EOL;
/** result :
Array
(
    [0] => blue
    [1] => yellow blue
)
blue exists ? yes
*/

answered Nov 3, 2013 at 0:28

OneOfOne

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