find a specific string pattern in an array jquery

Question

Apologies if this is a duplicate, but I can't seem to find the solution. I am trying to find a specific string pattern in an array. I want to find all values in data that contain 'underscore r underscore'. I then want to create a new array that contains only those keys and values.

var data = ["something", "bar_r_something"];
var resultArray = new Array();    
for (var i = 0; i < data.length; i++) {
    var bar = /_r_/;
    if ($.inArray(bar, data[i].length) > 0)
    {
       console.log("found _r_");
       resultArray.push(data[i]);
    }
};

I just can't seem to get that $.inArray to work, it seems to always kick out -1.

possible duplicate of Javascript - search for a string inside an array of strings — JJJ
– JJJ, Commented Nov 4, 2013 at 9:56

benhowdle89 · Accepted Answer · 2013-11-04 10:01:15Z

5

var data = ["something", "bar_r_something"];
var resultArray = new Array();
for (var i = 0; i < data.length; i++) {
    var bar = /_r_/;
    if (bar.test(data[i])) {
        alert("found _r_");
        resultArray.push(data[i]);
    }
};

console.log(resultArray);

Here you go, it doesn't use $.inArray, but Regex instead, hope that's cool!

EDIT

If you wanted to go a bit more fancy, you can use JavaScript's filter method like so:

var data = ["something", "bar_r_something"];
var resultArray = data.filter(function(d){
    return /_r_/.test(d);
});

console.log(resultArray);

edited Nov 4, 2013 at 10:01

answered Nov 4, 2013 at 9:54

benhowdle89

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Comments

Arun P Johny · Accepted Answer · 2013-11-04 09:58:41Z

2

I think what you are looking for is $.grep(). Also $.inArray() does not test the values against a regex, it tests for equality.

var regex = /_r_/
var resultArray  = $.grep(data, function(item){
    return regex.test(item)
})

Demo: Fiddle

answered Nov 4, 2013 at 9:58

Arun P Johny

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