Django custom management command with variable length of args list

Question

I'm writing a custom django management command.

class Command(BaseCommand):

    option_list = BaseCommand.option_list + (
        make_option(
            "-i",
            "--user_id",
            dest="user_id",
        ),
        make_option(
            "-f",
            "--fields",
            dest="fields"
        ),
    )

I need fields to consist of multiple elements. I know about nargs but I need to specify an exact number. My fields can vary from 1 to 5 elements. Is there a proper way to work with such args lists?

sjaensch · Accepted Answer · 2013-11-04 11:43:46Z

2

It's not possible to do this automatically. But you can work with a different action type:

option_list = BaseCommand.option_list + (
    make_option(
        "-i",
        "--user_id",
        dest="user_id",
    ),
    make_option(
        "-f",
        "--fields",
        dest="fields",
        action="append",
    ),
)

Now supply multiple field names at the command line like so:

./my_program -u my_user -f field1 -f field2 -f field3

options['fields'] will then contain a list of field names or None. You can check for this (and the fact that the list is longer than five elements) and print an error message.

answered Nov 4, 2013 at 11:43

sjaensch

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