Python random numbers multiple times

Question

import random

def main():
    uinput()

def uinput():
    times = int(input('How many numbers do you want generated?'))
    number1 = int(input('Put in the first number:' ))
    number2 = int(input('Put in the second number:'))
    rnumber = random.randint(number1, number2)
    print (rnumber)



main()

I am messing around in Python, and I want my program to generate random numbers. As you can see I have already accomplished this. The next thing I want to do is have it generate multiple random numbers, depending on how many numbers the "user" wants generated. How would I go about doing this? I am assuming a loop would be required.

If you know the range you want to pick from, you can also use random.choices(range, k=n), where n is the number of numbers to yield. — Eduardo Pignatelli
– Eduardo Pignatelli, Commented Sep 27, 2019 at 14:38

Aesthete · Accepted Answer · 2013-11-05 00:22:31Z

8

This will produce a list of random integers in range number1 to number2

rnumber = [random.randint(number1, number2) for x in range(times)]

For more information, look at List Comprehension.

answered Nov 5, 2013 at 0:22

Aesthete

18.9k6 gold badges38 silver badges46 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

John Hartman · Accepted Answer · 2017-10-26 04:28:59Z

2

I would recommend using a loop that simply adds to an existing string:

import random
from random import randint
list=""
number1=input("Put in the first number: ")
number2=input("Put in the second number: ")
total=input("Put in how many numbers generated: ")
times_run=0
while times_run<=total:
    gen1=random.randint(number1, number2)
    list=str(list)+str(gen1)+" "
    times_run+=1
print list

answered Oct 26, 2017 at 4:28

John Hartman

211 bronze badge

Comments

Joohwan · Accepted Answer · 2013-11-05 00:17:38Z

1

Use a "for" loop. For example:

for i in xrange(times):
    # generate random number and print it

answered Nov 5, 2013 at 0:17

Joohwan

2,5421 gold badge23 silver badges31 bronze badges

Comments

onemouth · Accepted Answer · 2013-11-05 02:34:27Z

1

Use generators and iterators:

import random
from itertools import islice

def genRandom(a, b): 
    while True:
        yield random.randint(a, b)


number1 = int(input('Put in the first number:' ))
number2 = int(input('Put in the second number:'))
total = int(input('Put in how many numbers generated:'))

rnumberIterator = islice(genRandom(number1, number2), total)

answered Nov 5, 2013 at 2:34

onemouth

2,28717 silver badges33 bronze badges

Comments

Timothy Woodard · Accepted Answer · 2022-08-12 18:22:46Z

0

You can define a function to take user input to generate numbers in a given range. You can return the function or print the function.

import random

def ran_nums():
    low_range = int(input('Enter the low end of the range: '))
    high_range = int(input('Enter the high end of the range: '))
    times = int(input('How many numbers do you want to generate? '))
    for num in range(times):
        print(random.randint(low_range,high_range))

answered Aug 12, 2022 at 18:22

Timothy Woodard

214 bronze badges

Comments

Donald Duck is with Ukraine · Accepted Answer · 2017-06-12 09:37:23Z

-2

This code chooses a random number:

import random
x = (random.randint(1, 50))
print ("The number is ", x)

Repeat the code 6 times to choose 6 random numbers.

edited Jun 12, 2017 at 9:37

Donald Duck is with Ukraine

9,00223 gold badges82 silver badges106 bronze badges

answered Jun 12, 2017 at 9:10

samuel

1

Collectives™ on Stack Overflow

Python random numbers multiple times

6 Answers 6

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

6 Answers 6

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related