Replace part of one string variable with another in a batch file

Question

I'm trying to run a command on all files within a directory (and its child directories) but am struggling to generate a relative path for the files I find.

The code I have is...

@echo off

set currentDir=%~dp0

for /r %%f in (*.js) do (
    echo %currentDir%
    echo %%f

    set relativePath=%%%f:%currentDir%=%
    echo %relativePath%
)

Basically if I run the script in C:\somedir and it finds C:\somedir\anotherdir\file.js I need %relativePath% to contain only anotherdir\file.js

Please help!

MC ND · Accepted Answer · 2013-11-06 09:01:19Z

2

EDITED - to adapt to required output.

 @echo off

    setlocal enableextensions enabledelayedexpansion

    rem to take batch file directory as current directory
    set "currentDir=%~dp0"

    rem OR to take current directory as current directory
    set "currentDir=%cd%"

    rem Select only one of the above

    rem add trailing backslash if not present
    if not "%currentDir:~-1%"=="\" set "currentDir=%currentDir%\"

    rem Do recurse directory
    for /r %%f in (*.js) do (
        set "relativePath=%%f"
        set "relativePath=!relativepath:%currentDir%=!"
        echo %relativePath%
    )

answered Nov 6, 2013 at 9:01

MC ND

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2 Comments

npocmaka Over a year ago

+1, but I love the endlocals when setlocal is used :-).It's more neat.

MC ND Over a year ago

@npocmaka : I agree. I've not included it thinking batch file will need more content. Anyway, endlocal is implicit and at end of batch file execution, any pending setlocal is canceled. It's only mandatory if you need to ensure, after a setlocal has been emited, that changes to environment variables persist. BUT, yes, i prefer balanced code.

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