PHP - Get raw image data from image in a HTML document

Question

How do i properly grab an image that is displayed in a HTML document and feed it to PHP to be read as image binary. I do not have direct access to the image file. The image i am trying to grab is fed to the client with HTML via PHP and printed in HTML format and using an <img> tag to display the image. The src is just a link to the same page i am currently on. The link is a GET request.

The link looks like this:

GETIMAGE.php?type=small&path=/path/to/image.png

This does not return the actual image with image MIME types. But rather a HTML displaying the image.

I do not have access to the source code in GETIMAGE.php file. This is encrypted as i am using a portal solution that is licensed.

This is the source that is returned from the GETIMAGE.php script:

<html>
<head>
    <meta name="viewport" content="width=device-width">
    <title>GETIMAGE.php (80×112)</title>
    <style type="text/css"></style>
</head>
<body style="margin: 0px;">
    <img style="-webkit-user-select: none" src="http://portal.craftnordic.com/PORTAL/GETIMAGE.php?type=small&amp;path=Path/To/Image.png">
</body>

@Lee I do not have access to the GETIMAGE.php code. It is encrypted as it is part of a licensed application called Xinet WebNative Portal. — Alex
– Alex, Commented Nov 6, 2013 at 14:29
possible duplicate of How do you parse and process HTML/XML in PHP? — Quentin
– Quentin, Commented Nov 6, 2013 at 14:32
In which case, can you post a "view source" of the GETIMAGE.php script so we know exactly what data your working with. I have a feeling the GETIMAGE script has a referrer check on it, that will only output the raw image data if the script is called from itself (based on your comments to previous answers) — Lee
– Lee, Commented Nov 6, 2013 at 14:41
@Lee Added the source that is returned from the GETIMAGE.php file. — Alex
– Alex, Commented Nov 6, 2013 at 14:51

David · Accepted Answer · 2013-11-06 14:40:01Z

1

Without seeing your script, it is hard to figure out what you are looking for. Let's assume the page generates output like this:

<img src="http://imgplacewhatever.com/lskjdflksdjf.png" />

Using this excellent DOM Parsing Library, we can do something like this:

$html = file_get_html('GETIMAGE.php?type=small&path=/path/to/image.png');
$pictures = array();
foreach($html->find('img') as $element) 
   $pictures[] = $element->src;
}

foreach ($pictures as $picture) {
   $data = file_get_contents($picture);
   ## Do something with the data.
}

Then you will have an array of all pictures in $pictures.

Good luck.

edited Nov 6, 2013 at 14:40

answered Nov 6, 2013 at 14:30

David

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6 Comments

Alex Over a year ago

I have also tried this. This will return the links of all images in the HTML. The link is just the same link as i am reading the HTML document from. This will not give me raw image data. (which is what i need)

David Over a year ago

You can use file_get_contents to get the stream. The answer was updated.

Alex Over a year ago

This will not work (already tried). It reads in the HTML that the image is displayed on and not the raw image data.

David Over a year ago

I understand. If you use the DOM parser and get the absolute URLs of the image, you can use file_get_contents() to get the data stream.

Alex Over a year ago

I have already tried the DOM parser library. It didn't get me anywhere. There is no direct link to the images, only a PHP script that prints them out in a HTML document. The images them self are stored in a safe folder on a different server. I work on 2 servers. One is the data server that holds all the data, and the other displays it to the user. I am currently on the server that displays data.

|

Pavan Kumar · Accepted Answer · 2013-11-06 14:29:32Z

0

You can use file_get_contents() method to get the data.

Here you can use

$filePath=$_GET['path'];
$imageData=file_get_contents($filePath);

answered Nov 6, 2013 at 14:29

Pavan Kumar

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4 Comments

Alex Over a year ago

I have already tried this method. This will read the HTML document the image is displayed on, and not the raw image data. I need it to be raw image data.

Pavan Kumar Over a year ago

Sorry i didn't get you for example if i use $imageData=file_get_contents('google.co.in/images/srpr/logo11w.png'); then that will load the google logo icon binary data to $imageData

Pavan Kumar Over a year ago

Try to specify the exact path of image like this

Alex Over a year ago

I do not have exact images path, and nor do i have direct access to it. It is running on a data server that transfers the content to the other server that grabs the data from the data server and sends it to a client.

Jennifer Chalek · Accepted Answer · 2014-10-21 19:53:00Z

0

Don't know if you ever found an answer, but I finally did. The data that was being received by file_get_contents - or any CURL method - was actually returning data in a gzip format. When I saved the output to a file and extracted it as a gzip archive, the image was there.

answered Oct 21, 2014 at 19:53

Jennifer Chalek

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