I would like to extract the first comment block of a CSS file which is like this :
/*
author : name
uri : link
etc
*/
without extracting the other comments
/* header */
/* footer */
So I tried this :
print re.findall(r'\/\*(.*)\*\/', cssText )
this gave me all the other comments except the block I need. so I changed it into this, to be more precise :
print re.findall(r'\/\*\n(.*)^\*\/', cssText )
and the result was nothing :
[]
Do you have suggestions? Thanks :-)
If you only need the first comment you can simply only use the first result:
print re.findall(r'\/\*(.*)\*\/', cssText )[0]
You can also use re.search which searches for the first matching occurrence:
print re.search(r'\/\*(.*)\*\/', cssText )
[0] gave me the first comments just after the block I need. The other one works with .group() and it give the same result as the first.When you match multi line string, you need to make . match \n too:
print re.findall(r'\/\*\n(.*?)\*\/', cssText, re.S)
You can do this:
css = """
/*
author : name
uri : link
etc
*/
bla bla bla. Blah blah
x: 10;
color: red;
/* header */
/* footer */
"""
import re
pat = r'\/\*([\S\s]*?)\*\/'
print re.findall(pat, css)
print re.search(pat, css).group()
