PHP Nested Array - Output sub-array contents and array name

Question

Consider this nested array:

$link = array(
 'Level 1' => array(
   'Monthly' => array( 
    'note' => 'Note 1 1',
    'link'  => '1.1.com',
    ),
   '6 Month' => array(  
     'note' => 'Note 1 6',
     'link' => '1.6.com',
    ),
 ),
 'Level 2' => array(
   'Monthly' => array( 
    'note' => 'Note 2.1',
    'link'  => '2.1.com',
    ),
   '6 Month' => array(  
     'note' => 'Note 2.6',
     'link' => '2.6.com',
    ),
 ),

How would I gracefully use a foreach to achieve the following:

if $var = 'Level 1' output 

  <a href="1.1.com" title="Note 1 1">Monthly</a>
  <a href="1.6.com" title="Note 1 6">6 Month</a>

I'm suspecting I might need to do a loop inside a loop? I can iterate through the array, but am having trouble figuring out how to call the name of the sub-array...

To think, I put the vars in arrays thinking it would be easier... bah — OliverSamson43
– OliverSamson43, Commented Nov 8, 2013 at 2:52
I'm thinking I should refactor the 'Monthly' into the same level as the note and link vars... in a numeric array... — OliverSamson43
– OliverSamson43, Commented Nov 8, 2013 at 2:56

Darren · Accepted Answer · 2013-11-08 03:07:21Z

1

<?php
$key = 'Level 1';

$link = array(
 'Level 1' => array(
   'Monthly' => array( 
    'note' => 'Note 1 1',
    'link'  => '1.1.com',
    ),
   '6 Month' => array(  
     'note' => 'Note 1 6',
     'link' => '1.6.com',
    ),
 ),
 'Level 2' => array(
   'Monthly' => array( 
    'note' => 'Note 2.1',
    'link'  => '2.1.com',
    ),
   '6 Month' => array(  
     'note' => 'Note 2.6',
     'link' => '2.6.com',
    ),
 ),
);

if(isset($link[$key])) {
    foreach($link[$key] as $array) {
        print_r($array);
    }
}
?>

RETURNS

Array
(
    [note] => Note 1 1
    [link] => 1.1.com
)
Array
(
    [note] => Note 1 6
    [link] => 1.6.com
)

I check to see if it is set first and then run a foreach on the set key to print out what you need.

EDIT:

if(isset($link[$key])) {
    foreach($link[$key] as $key => $array) {
        print $key;
        print_r($array);
    }
}

Which returns

Monthly
Array
(
    [note] => Note 1 1
    [link] => 1.1.com
)
6 Month
Array
(
    [note] => Note 1 6
    [link] => 1.6.com
)

edited Nov 8, 2013 at 3:07

answered Nov 8, 2013 at 2:35

Darren

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4 Comments

OliverSamson43 Over a year ago

Yes! This is the step ($link[$key]) I was f-ing ripping my hair out over... so simple once I see it. This is why I love SO

fluke Over a year ago

great. you got @OliverSamson43's intention.

OliverSamson43 Over a year ago

But wait... how do I ouput the name of the arrays? (Monthly and 6 Month...)

OliverSamson43 Over a year ago

I know, right? @fluke -- I'm so messed up in code right now, I don't know which way is up...

fluke · Accepted Answer · 2013-11-08 02:33:29Z

0

I think using nested loop in this case is graceful.

Just use two foreach.

answered Nov 8, 2013 at 2:33

fluke

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2 Comments

OliverSamson43 Over a year ago

So, when I'm in the second nested loop, how do I get the parent of that loop?

fluke Over a year ago

in every foreach loop you get a $key and a $value. $key and $value in the parent loop are from the parent. inside the parent loop, you can do a foreach to the value to get sub data.

aemad · Accepted Answer · 2013-11-09 03:16:18Z

0

that's how it'd look like if you're trying to define the arrays within the main array

    foreach ($link  as $sub_array) {
        //do something
        foreach ($sub_array as $sub_of_sub) {
            // do something and so on
        }
    }

edited Nov 9, 2013 at 3:16

answered Nov 8, 2013 at 2:38

aemad

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