How to return a fixed length binary representation of an integer in Ruby?

Question

I know that I can use Fixnum#to_s to represent integers as strings in binary format. However 1.to_s(2) produces 1 and I want it to produce 00000001. How can I make all the returned strings have zeros as a fill up to the 8 character? I could use something like:

binary = "#{'0' * (8 - (1.to_s(2)).size)}#{1.to_s(2)}" if (1.to_s(2)).size < 8

but that doesn't seem very elegant.

sawa · Accepted Answer · 2013-11-08 07:23:44Z

9

Use string format.

"%08b" % 1
# => "00000001"

answered Nov 8, 2013 at 7:23

sawa

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falsetru · Accepted Answer · 2013-11-08 07:28:21Z

8

Using String#rjust:

1.to_s(2).rjust(8, '0')
=> "00000001"

answered Nov 8, 2013 at 7:28

falsetru

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tihom · Accepted Answer · 2013-11-08 07:31:47Z

4

Use the String#% method to format a string

 "%08d" % 1.to_s(2)
 # => "00000001"

Here is a reference for different formatting options.

edited Nov 8, 2013 at 7:31

answered Nov 8, 2013 at 7:22

tihom

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1 Comment

Arup Rakshit Over a year ago

Great Link and Nice answer(+1)

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