I have 5 php scripts need to be executed one after other. How can i create a single php/batch script which executes all the php scripts in sequence.
I want to schedule a cron which run that php file.
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what do you have so far?pregmatch– pregmatch2013-11-08 10:38:36 +00:00Commented Nov 8, 2013 at 10:38
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2 Answers
#!/path/to/your/php
<?php
include("script1.php");
include("script2.php");
include("script3.php");
//...
?>
Alternative
#/bin/bash
/path/to/your/php /path/to/your/script1.php
/path/to/your/php /path/to/your/script2.php
/path/to/your/php /path/to/your/script3.php
# ...
If your scripts need to be accessed via http:
#/bin/bash
wget --quiet http://path/to/your/script1.php > /dev/null 2>&1
wget --quiet http://path/to/your/script2.php > /dev/null 2>&1
wget --quiet http://path/to/your/script3.php > /dev/null 2>&1
# ...
3 Comments
user2129794
what about using exec?? instead of include as there may be some clashing of variables if i use include
Gerald Schneider
If you keep your code clean there is no need to start more shell and php instances.
davea0511
It's not a cleanliness issue ... it's a housekeeping issue, and it can be a pain in the neck making sure all your variables unique names if you don't want them treated globally, but that's what you have to do. I kind of hate this about the include function.
I did something for testing using the "wait" command, as it seems I just put wait between the calls to each script. I did a little test creating databases in php scripts, returning some records in a bash script, then updating with another php script, then another bash script to return the updated results and it seemed to work fine...
From what I have read, as long as the subscript doesn't call another subscript, the master script will wait if "wait" command is used between script calls.
Code is as below:
#!/bin/sh
/usr/bin/php test.php
wait
/bin/bash test.sh
wait
/usr/bin/php test2.php
wait
/bin/bash test2.sh
wait
echo all done
Hope it would execute all the php scripts in sequence.
