Remove empty strings from array while keeping record Without Loop?

Question

This question was asked here: Remove empty strings from array while keeping record of indexes with non empty strings

If you'd notice the given as @Baz layed it out;

"I", "am", "", "still", "here", "", "man"

"and from this I wish to produce the following two arrays:"

"I", "am", "still", "here", "man"

All the Answers to this question referred to a form of looping.

My question: Is there a possibility to remove all indexes with empty string without any looping? ... is there any other alternative apart from iterating the array?

May be some regex or some jQuery that we are not aware of?

All answers or suggestions are highly appreciated.

Isaac · Accepted Answer · 2016-04-23 03:56:48Z

340

var arr = ["I", "am", "", "still", "here", "", "man"]
// arr = ["I", "am", "", "still", "here", "", "man"]
arr = arr.filter(Boolean)
// arr = ["I", "am", "still", "here", "man"]

filter documentation

// arr = ["I", "am", "", "still", "here", "", "man"]
arr = arr.filter(v=>v!='');
// arr = ["I", "am", "still", "here", "man"]

Arrow functions documentation

edited Apr 23, 2016 at 3:56

answered Nov 10, 2013 at 10:41

Isaac

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6 Comments

Isaac Over a year ago

I know exactly how you feel, I used it months ago, fixes so many small issues

Isaac Over a year ago

@DiegoPlentz people who're still running IE8 are gonna have a lot more problems than just removing blanks in an array... I barely ever consider supporting that browser these days

james_womack Over a year ago

This is the closest to array.filter(!!) that we can currently get :)

Isaac Over a year ago

All credit for this answer should go to stackoverflow.com/questions/16701319/…

robsch Over a year ago

Some explanation regarding Boolean would be nice.

|

Haitham Ahmed · Accepted Answer · 2014-03-11 21:34:20Z

19

var newArray = oldArray.filter(function(v){return v!==''});

answered Mar 11, 2014 at 21:34

Haitham Ahmed

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1 Comment

Bryan Over a year ago

Easily the best answer. Does exactly what the question asks. Doesn't remove zero values.

ErickBest · Accepted Answer · 2013-11-10 10:52:43Z

PLEASE NOTE: The documentation says:

filter is a JavaScript extension to the ECMA-262 standard; as such it may not be present in other implementations of the standard. You can work around this by inserting the following code at the beginning of your scripts, allowing use of filter in ECMA-262 implementations which do not natively support it. This algorithm is exactly the one specified in ECMA-262, 5th edition, assuming that fn.call evaluates to the original value of Function.prototype.call, and that Array.prototype.push has its original value.

So, to avoid some heartache, you may have to add this code to your script At the beginning.

if (!Array.prototype.filter) {
  Array.prototype.filter = function (fn, context) {
    var i,
        value,
        result = [],
        length;
        if (!this || typeof fn !== 'function' || (fn instanceof RegExp)) {
          throw new TypeError();
        }
        length = this.length;
        for (i = 0; i < length; i++) {
          if (this.hasOwnProperty(i)) {
            value = this[i];
            if (fn.call(context, value, i, this)) {
              result.push(value);
            }
          }
        }
    return result;
  };
}

haind · Accepted Answer · 2019-01-11 03:27:06Z

4

arr = arr.filter(v => v);

as returned v is implicity converted to truthy

answered Jan 11, 2019 at 3:27

haind

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Comments

Isaac · Accepted Answer · 2017-04-27 04:14:02Z

2

If are using jQuery, grep may be useful:

var arr = [ a, b, c, , e, f, , g, h ];

arr = jQuery.grep(arr, function(n){ return (n); });

arr is now [ a, b, c, d, e, f, g];

edited Apr 27, 2017 at 4:14

Isaac

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answered Oct 28, 2014 at 14:18

sansid1983

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1 Comment

Isaac Over a year ago

jquery seems like a lot of bulkiness for a menial task

Esin ÖNER · Accepted Answer · 2019-12-23 12:26:04Z

1

You can use lodash's method, it works for string, number and boolean type

_.compact([0, 1, false, 2, '', 3]);
// => [1, 2, 3]

https://lodash.com/docs/4.17.15#compact

answered Dec 23, 2019 at 12:26

Esin ÖNER

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Comments

Atif Hussain · Accepted Answer · 2016-09-15 12:38:00Z

0

i.e we need to take multiple email addresses separated by comma, spaces or newline as below.

    var emails = EmailText.replace(","," ").replace("\n"," ").replace(" ","").split(" ");
    for(var i in emails)
        emails[i] = emails[i].replace(/(\r\n|\n|\r)/gm,"");

    emails.filter(Boolean);
    console.log(emails);

answered Sep 15, 2016 at 12:38

Atif Hussain

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1 Comment

Isaac Over a year ago

.replace(" ","").split(" ") "replace all spaces with nothing, then try split at every space"

abdallah eslah · Accepted Answer · 2024-12-17 21:49:17Z

0

You can use where it's very simple:

roomProvider.roomsList?.where((room) => room.roomDestination != '');

answered Dec 17, 2024 at 21:49

abdallah eslah

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