How do you create an array from variables derived from a foreach loop?

Question

I'm certain this is VERY simple, but being new and not knowing what I'm doing I can't quite get it on my own.

I am trying to create an array of wordpress post ID's that is derived from a simple foreach loop.

Basically I have this as my code:

$omit_these_quizzes = array();    
foreach ( $filtered_pass as $single_quiz ) {
    $quiz_id_number =  $single_quiz['quiz'];
    $omit_these_quizzes[] = $quiz_id_number;
}

I would like to take each of the resulting $quiz_id_number 's and have then end up in array that looks like this:

$omit_these_quizzes = array(8195,8193);

However, I keep ending up with an array that only contains the variable from the very last foreach loop, instead of them all. What am I doing wrong?

Thanks!

Your code looks fine, so either $filtered_pass contains only one id, or the result in $omit_these_quizzes is okay, but you inspect/process it in the wrong way. — GolezTrol
– GolezTrol, Commented Nov 11, 2013 at 8:30
I believe your code is supposed to work correctly, but you can try this. php.net/manual/en/function.array-push.php — TheNavigat
– TheNavigat, Commented Nov 11, 2013 at 8:31

Community · Accepted Answer · 2023-11-20 22:45:59Z

1

Your code looks fine.But if you want alternative try this:
see here for in_array and array_push.

$omit_these_quizzes = array();    
foreach ( $filtered_pass as $single_quiz ) 
{
   $quiz_id_number =  $single_quiz['quiz'];
   if(!in_array($quiz_id_number ,$omit_these_quizzes))
   {
     array_push($omit_these_quizzes, $quiz_id_number);
   }
}

hope it's help you.

edited Nov 20, 2023 at 22:45

CommunityBot

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answered Nov 11, 2013 at 8:38

DS9

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3 Comments

Nathaniel Miller Over a year ago

Thanks! I guess the if statement prevents my array from doubling up on id's? That seems to keep things clean and tidy. Thanks for the added bonus :-)

Nathaniel Miller Over a year ago

The if statement that you threw in helped me out tremendously with another piece of code. Double thanks to you.

DS9 Over a year ago

you always welcome and yes the if statement prevents duplicate entry.

J.Koskela · Accepted Answer · 2013-11-11 08:32:52Z

1

This work?

$omit_these_quizzes = array();    
foreach ( $filtered_pass as $single_quiz ) {
    $quiz_id_number =  $single_quiz['quiz'];
    array_push($omit_these_quizzes, $quiz_id_number);
}

answered Nov 11, 2013 at 8:32

J.Koskela

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1 Comment

Nathaniel Miller Over a year ago

Thanks! It does exactly what I was hoping for :-)

Shally Virk · Accepted Answer · 2013-11-11 08:34:06Z

1

Looks like you are creating a new array in each loop, that's why you end up with an array containing just a single element... Use:

$omit_these_quizzes = array();    
foreach ( $filtered_pass as $single_quiz ) 
{
    $quiz_id_number =  $single_quiz['quiz'];
    array_push($omit_these-quizzes, $quiz_id_number);
}

answered Nov 11, 2013 at 8:34

Shally Virk

595 bronze badges

1 Comment

Nathaniel Miller Over a year ago

Thanks! This code did exactly what I was looking for. Thanks for explaining why my old one wasn't working ^_^

Nikolay Krasnov · Accepted Answer · 2013-11-11 08:38:20Z

0

Your code is correct. Inspect your $filtered_pass variable by calling var_dump($filtered_pass); may be it contain only one subarray.

answered Nov 11, 2013 at 8:38

Nikolay Krasnov

3731 silver badge14 bronze badges

1 Comment

Nathaniel Miller Over a year ago

I did check my $filtered_pass array, although I was using return print_r to check instead of var_dump like you suggested. Is var_dump the 'correct' way of checking? There were indeed multiple sub-arrays btw.

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