Python get generated url to string

Question

(Title might change not too sure what to call it)

So I'm trying to open a URL that directs to a random page (This URL: http://anidb.net/perl-bin/animedb.pl?show=anime&do.random=1) and I want to return where that URL goes

    randomURL = urllib.urlopen("http://anidb.net/perl-bin/animedb.pl?show=anime&do.random=1")
    print(randomURL)

That's what I (stupidly) thought would work. I imported urllib

So you want to detect what URL a different URL gets redirected to? Is that right? — Matt Dodge
– Matt Dodge, Commented Nov 12, 2013 at 1:11

aIKid · Accepted Answer · 2013-11-12 01:15:58Z

1

In Python 3 >, urllib.urlopen was replaced by urllib.request.urlopen. Change the request line to this:

urllib.request.urlopen('http://anidb.net/perl-bin/animedb.pl?show=anime&do.random=1')

For more, you can see the docs

But if you want to have the url, which is a bit more difficult, you can take a look at urllib.request.HTTPRedirectHandler

answered Nov 12, 2013 at 1:00

aIKid

28.5k5 gold badges41 silver badges65 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

The questioner wants to get the final URL (ie the URL that is redirected to).