print 077777#how can i get binary
i use python2.5
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1are you asking how you can print an integer in binary?President James K. Polk– President James K. Polk2010-01-03 03:27:45 +00:00Commented Jan 3, 2010 at 3:27
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4 Answers
Make a map of hexadecimal characters to binary sequences, then run the number through (note: only works for non-negative numbers):
def bin(value):
binmap = {'0': '0000', '1': '0001', ..., 'f': '1111'}
return ''.join(binmap[x] for x in ('%x' % (value,))).lstrip('0') or '0'
answered Jan 3, 2010 at 3:31
Ignacio Vazquez-Abrams
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2 Comments
bobince
I'd probably make this return
0b prepended, for compatibility with the built-in bin function present in Python 2.6.
Oleh Prypin
return '-0b'[value>=0:] + ... % (abs(value),) ... to make it support negative numbers and be compatible with binSimplest (not fastest!) way to get a binary string for an int in Python 2.5:
def dobin(n):
digs = []
s = ''
if n<0:
s = '-'
n = -n
while True:
digs.append(str(n % 2))
n /= 2
if not n: break
if s: digs.append(s)
digs.reverse()
return ''.join(digs)
Are you looking for speed, or for clarity?
Comments
Here are some recipes from ActiveState Code you might find helpful: Format integer as binary string
My initial answer only works in Python 2.6 and up as Alex correctly pointed out.
Like this:
print '{0:b}'.format(077777)
Comments
n = 1234
"".join([["0", "1"][(n >> i) & 1] for i in reversed(range(n.__sizeof__()))])
although not sure if sizeof its correct.you could also calculate the highest bit set and only print those.
"".join([["0", "1"][(n>>i)&1] for i in range(log(n,2)+1)])
