jQuery input name argument

Question

How do we put agru inside function $('input[name=agru]')

 function changeBackground(agru){
      $('input[name=agru]').css('background','red');
}

$('input[name=agru]') isn't right. How do I escape? Thanks

Community · Accepted Answer · 2017-05-23 12:05:02Z

2

Use

function addBorder(agru) {
    $('input[name=' + agru + ']').css('background', 'red');
}

CommunityBot

11 silver badge

answered Nov 13, 2013 at 3:52

57.2k24 gold badges106 silver badges110 bronze badges

Sign up to request clarification or add additional context in comments.

1 Answer 1