Javascript refresh query database?

Question

This is the website: enter link description here

Right now this is the function:

$("a.wtf").click(function(){
//get the id
the_id = $(this).attr('id');

// show the spinner
$(this).parent().html("<img src='images/thanks.fw.png'/>");

//the main ajax request
    $.ajax({
        type: "POST",
        data: "action=wtf&id="+$(this).attr("id"),
        url: "votes.php",
        success: function(msg)
        {
            $("span#votes_count"+the_id).fadeOut();
            $("span#votes_count"+the_id).html(msg);
            $("span#votes_count"+the_id).fadeIn();
            $("span#vote_buttons"+the_id).remove();
        }
    });
});

And this is the rest:

<a href='javascript:;' class='wtf' id='".$list['id']."'>

Rephrased: Right now, it displays an image after a user VOTES "WTF". How would I replace the Vote link with new text displaying the new value of the WTF vote (probably a result of the query)

Will you bother to rephrase your question

pratim_b
– pratim_b

2013-11-14 05:27:06 +00:00
Commented Nov 14, 2013 at 5:27 — pratim_b
– pratim_b, Commented Nov 14, 2013 at 5:27
sure, done. Sorry man. I'm a moron.

user2990466
– user2990466

2013-11-14 05:34:39 +00:00
Commented Nov 14, 2013 at 5:34 — user2990466
– user2990466, Commented Nov 14, 2013 at 5:34
your question is not clear.

Vijay Verma
– Vijay Verma

2013-11-14 05:56:24 +00:00
Commented Nov 14, 2013 at 5:56 — Vijay Verma
– Vijay Verma, Commented Nov 14, 2013 at 5:56

senthil · Accepted Answer · 2013-11-14 05:40:33Z

1

Once you send the votes.php, hope you are update or insert the new vote, if is happenings like what i mention in this means , you also fetch the newly inserted or updated values from db then return to the callback function

Example :

    $total_votes=100;
    $reuslut=$total."-".'Thanks for vote';
    echo $result;
    exit;

 in call back function :
 ---------------------

    success: function(msg)
    {
       var value=msg.split("-");
        $("span#votes_count"+the_id).fadeOut();
        $("span#votes_count"+the_id).html(value[1]);
        $("span#votes_count"+the_id).fadeIn();
        $("span#vote_buttons"+the_id).remove();
        $(selector).html(value[1]);
    }

Hope it will help you for your question

answered Nov 14, 2013 at 5:40

senthil

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