Converting multiple arrays into a single hash

Question

I'm working on a configuration file parser and I need help parsing key: value pairs into a hash.

I have data in the form of: key: value key2: value2 another_key: another_value.

So far I have code in form of

    line = line.strip!.split(':\s+')

which returns an array in the form of

["key:value"]["key2: value2"]["another_key: another_value"]

How can I turn these arrays into a single hash in the form of

{key=>value, key2=>value2, another_key=>another_value}

I'm not sure if the key:value pairs need to be in the form of a string or not. Whatever is easiest to work with.

Thanks for your help!

This is the solution I found:

    line = line.strip.split(':')
    hash = Hash[*line]

which results in the output{"key"=>"value"}, {"key2"=>"value2"}

Have a look at String#partition. That would be ideal for splitting each string into key and value, or use a regex with a capture group on each side of the colon. — Cary Swoveland
– Cary Swoveland, Commented Nov 15, 2013 at 2:20
Ah nice, String#partition is a useful method! Thanks @CarySwoveland — Anish Kothari
– Anish Kothari, Commented Nov 15, 2013 at 2:32

hirolau · Accepted Answer · 2013-11-15 15:40:12Z

1

Very very close to Cary's solution:

Hash[*line.delete(':').split]

edited Nov 15, 2013 at 15:40

answered Nov 15, 2013 at 7:35

hirolau

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2 Comments

hirolau Over a year ago

That's why I still felt it was worth adding.

Cary Swoveland Over a year ago

Ah, the price of honesty. :-)

Cary Swoveland · Accepted Answer · 2013-11-15 02:40:50Z

1

Even simpler:

Hash[*line.gsub(':',' ').split]
  # => {"key"=>"value", "key2"=>"value2", "another_key"=>"another_value"}

edited Nov 15, 2013 at 2:40

answered Nov 15, 2013 at 2:35

Cary Swoveland

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1 Comment

Anish Kothari Over a year ago

Good solution, I used this to come up with something of my own

Nigel Thorne · Accepted Answer · 2013-11-15 05:15:01Z

1

Assuming the key and value are single words, I'd probably do something like this:

Hash[line.scan(/(\w+):\s?(\w+)/)]

You can change the regex if it's not quite what you are looking for.

answered Nov 15, 2013 at 5:15

Nigel Thorne

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1 Comment

Anish Kothari Over a year ago

Thanks @Nigel this works, but I'd rather not deal with the RegEx

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