php preg_match replace result duplicate

Question

I am a newbie in preg_match patterns, so I would be glad if someone could help me for next situation:

I need to replace those string:

[popup="about"]about me[/popup]

to

<a href="#PopupAbout"  data-plugin-options='{"type":"inline", preloader: false}'>about me</a>

I have tried with $pattern = '/\[popup="(.*?)"\](.*?)\[\/popup\]/'; but it does not give me expected result, it give duplicated results. And how can I replace it all in a simple way!

Regards!

Toto · Accepted Answer · 2013-11-16 13:24:45Z

1

How about:

$str = preg_replace('~\[popup="about"\](.+?)\[/popup\]'~, 
   "<a href=\"#PopupAbout\" data-plugin-options='{\"type\":\"inline\", preloader: false}'>$1</a>",
   $str);

answered Nov 16, 2013 at 13:24

Toto

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1 Comment

Xiabili Over a year ago

That looks like interesting, I will try this later at home

HamZa · Accepted Answer · 2013-12-22 11:51:16Z

0

Try this:

preg_match("/\[popup="(.*)"\](.*?)\[\/popup\]/", $input_line, $output_array);

I get this result:

Array
(
    [0] => [popup="about"]about me[/popup]
    [1] => about
    [2] => about me
)

You can test it online here: http://www.phpliveregex.com/

edited Dec 22, 2013 at 11:51

HamZa

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answered Nov 16, 2013 at 10:42

Albert Kozłowski

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1 Comment

HamZa Over a year ago

You should use a reluctant quantifier .*? instead of .*. See when it fails

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