undefined reference to function error in c

Question

#include <stdio.h>


int singleFib(int x,int a,int b);
int multiFib(int x);


void main(){
int n,i;
printf("How much?\n");
scanf("%d",&n);

for(i=0;i<n;i++){
    printf("%5d. number:   %d   -  %d \n",i+1,multiFib(i),singleFib(i,1,1));


}

getch();
return 0;

}

int multiFib(int x){

if (x<2){
    return 1;
}
else{
    return multiFib(x-2)+multiFib(x-1);
}


int singleFib(int x,int a,int b){

if (x<2){
    return 1;
}
else{

    return singleFib( x-1, b,(a+b));
}

}
}

The error is in

singleFib(i,1,1) in `printf`

Whyis that problem?how can i solve that problem? i am using codeblocks

Codeblocks\Fiberonacci\main.c|14|undefined reference to `singleFib'| The error is that.how can i solve?

You need to start indenting your code properly. Also, it's called Fibonacci, not Fiberonacci. — ThiefMaster
– ThiefMaster, Commented Nov 16, 2013 at 16:28
Welcome to SO! Can you not make a smaller example that fails in the same way? The question will be easier to answer, more useful to others, and you might just find the answer yourself this way. — Ciro Santilli OurBigBook.com
– Ciro Santilli OurBigBook.com, Commented Nov 16, 2013 at 16:28
Nested function is a GCC extension which some gcc-compatible compilers like icc do support. It's not portable. — Jack
– Jack, Commented Nov 16, 2013 at 16:34
This code is a good (or merely bad) example where proper indentation would have made the error immediately obvious. — Jens Gustedt
– Jens Gustedt, Commented Nov 16, 2013 at 16:34

godel9 · Accepted Answer · 2013-11-16 16:28:17Z

6

You're missing a close bracket } at the end of your multiFib function.
You have an extra close bracket } at the end of your singleFib function.
The function main should have return type int.

answered Nov 16, 2013 at 16:28

godel9

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Comments

score 1 · Accepted Answer · 2013-11-16 17:34:00Z

1

The { and } in multiFib and singleFib are mixed up, singleFib is declared inside multiFib:

int multiFib(int x){

    if (x<2){
        return 1;
    }
    else{
        return multiFib(x-2)+multiFib(x-1);
    }


    /*************************************/
    int singleFib(int x,int a,int b) {

        if (x<2){
            return 1;
        }
        else{

            return singleFib( x-1, b,(a+b));
        }
    }

    /*************************************/
}

it works in gcc, since it's an nonstandard nested functions extension, but the function will not be accessible outside multiFib.

edited Nov 16, 2013 at 17:34

answered Nov 16, 2013 at 16:32

user1129665

Comments

aks · Accepted Answer · 2013-11-16 16:28:51Z

0

Seems like there is a mismatch in the braces of the function definition

answered Nov 16, 2013 at 16:28

aks

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Comments

Eutherpy · Accepted Answer · 2013-11-16 16:35:51Z

0

You're missing a closing bracket for multiFib, but have one that you don't need after singleFib.

edited Nov 16, 2013 at 16:35

answered Nov 16, 2013 at 16:29

Eutherpy

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