TypeError in Jython?

Question

I'm trying to make two lines across a circle, like an X. Since it's an X, to find the (x,y) I just multiplied sqrt(2)/2 by the radius and then added or subtracted it from the (x,y) origin depending on what corner of the circle it was in. However I keep getting a TypeError 'The error was: 2nd arg can't be coerced to int' This is what I have:

#starting/ending points of the line
a1 = z - ((sqrt(2) / 2)*(r1))
b1 = w - ((sqrt(2) / 2)*(r1))
a2 = z + ((sqrt(2) / 2)*(r1))
b2 = w + ((sqrt(2) / 2)*(r1))
c1 = z - ((sqrt(2) / 2)*(r1))
d1 = w + ((sqrt(2) / 2)*(r1))
c2 = z + ((sqrt(2) / 2)*(r1))
d2 = w - ((sqrt(2) / 2)*(r1))
pic.addLine(black, a1, b1, a2, b2)
pic.addLine(black, c1, d1, c2, d2)

...where z is the x origin, w is the y origin, and r1 is the radius. What am I doing wrong here? This what I'm getting :

enter image description here

Have you tried turning the a1, b1, a2, b2, etc. arguments to integer yet? int(a1), int(b1), int(a2), int(b2)? — Martijn Pieters
– Martijn Pieters, Commented Nov 16, 2013 at 18:06
What gets displayed if you do print type(a1) right before you call pic.addLine? — Michael0x2a
– Michael0x2a, Commented Nov 16, 2013 at 18:15

Martijn Pieters · Accepted Answer · 2013-11-25 19:56:32Z

2

By using sqrt() you end up with floating point values, but the method you are calling wants integers only. Call int() on the values before passing them to pic.addLine():

pic.addLine(black, int(a1), int(b1), int(a2), int(b2))
pic.addLine(black, int(c1), int(d1), int(c2), int(d2))

answered Nov 25, 2013 at 19:56

Martijn Pieters

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