I am trying to split my string into a list, separating by whitespace and characters but leaving numbers together.
For example, the string:
"1 2 +="
would end up as:
["1", " ", "2", " " ,"+", "="]
The code I currently have is
temp = re.findall('\d+|\S', input)
This seperates the string as intended but does also remove the whitespace, how do I stop this?
Just add \s or \s+ to your current regular expression (use \s+ if you want consecutive whitespace characters to be grouped together). For example:
>>> s = "1 2 +="
>>> re.findall(r'\d+|\S|\s+', s)
['1', ' ', '2', ' ', '+', '=']
If you don't want consecutive whitespace to be grouped together, then instead of r'\d+|\S|\s' it would probably make more sense to use r'\d+|\D'.
You can use \D to find anything that is not a digit:
\d+|\D
Python:
temp = re.findall(r'\d+|\D', input)
//Output: ['1', ' ', '2', ' ', '+', '=']
It would also work if you just used . since it'll match the \d+ first anyway. But its probably cleaner not to.
\d+|.
\s?