Get Object Method Name From Within That Same Method

Question

Let's say I have an obj:

var app = {}

and a method inside the object

app = {
   init: function () {
   }
}

how would I go about obtaining the method name 'init' inside of init() without specifically looking for 'init'. This would be in the case that the method name could be anything and I can't rely on searching for a specific name.

app = {
   init: function () {
      //get 'init' method name here
   }
}
app.init();

I tried using callee but that brings back an empty string

sbking · Accepted Answer · 2013-11-19 20:02:07Z

3

You could use a named function expression:

app = {
  init: function init() {
    console.log(arguments.callee.name);
  }
};

app.init();  // => "init"

Note that use of arguments.callee is forbidden in strict mode.

What you are doing in your example is assigning an anonymous function expression to the property named init on your object. The function itself does not have a name unless you use a named function expression.

edited Nov 19, 2013 at 20:02

answered Nov 19, 2013 at 19:05

sbking

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3 Comments

spez86 Over a year ago

Thanks, something so simple, didn't even think about declaring its name. That worked perfectly

spez86 Over a year ago

I had used arguments.callee.name before, but for the life of me could not figure out why it was coming back as an empty string. Not declaring it was staring me right in the face. Ugh, need to step away for a little bit. Thanks again for your answer!

dandavis Over a year ago

just to be clear, that's actually a named function expression, not a function declaration.

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