How to add two arrays into one array in Javascript [duplicate]

Question

I am trying to add a couple of arrays into one array in Javascript. It seems my way is not good enough. Let's suppose we have these three arrays as below:

var array_1 = [{"a" : 1, "b" : 2, "c" : 3}];
var array_2 = [{"d" : 4, "e" : 5, "f" : 6}];
var array_3 = new Array();

I would like to add array_1 and then array_2 into array_3. For instance, I want to make sure that array_1 is fully added first and then array_2 as below:

{"a" : 1, "b" = 2, "c" = 3"}
{"d" : 4, "e" = 5, "f" = 6"}

Could anyone please help me with this piece of code. Your help would be very much appreciated.

Is there any special reason why your arrays have just one element? — Tibos
– Tibos, Commented Nov 20, 2013 at 22:44
Do you need an array with 2 objects or 1 object with "a" through "f" keys? — mdolbin
– mdolbin, Commented Nov 20, 2013 at 22:46

Justin Niessner · Accepted Answer · 2013-11-20 22:44:24Z

4

var array_3 = array_1.concat(array_2);

answered Nov 20, 2013 at 22:44

Justin Niessner

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MattDiamant · Accepted Answer · 2013-11-20 22:47:54Z

1

The way that you have your arrays set up is very strange. What you have are 2 arrays with 1 element in them each, and that element is an Object with 3 properties. The output that you listed is actually invalid javascript or JSON syntax. But, I can get you close to what you want, I think...

var array_1 = [{"a" : 1, "b" : 2, "c" : 3}];
var array_2 = [{"d" : 4, "e" : 5, "f" : 6}];
var array_3 = new Array();

function merge_objects(obj1,obj2){
    var obj3 = {};
    for (var attrname in obj1) { obj3[attrname] = obj1[attrname]; }
    for (var attrname in obj2) { obj3[attrname] = obj2[attrname]; }
    return obj3;
}

array_3[0] = merge_objects(array_1[0], array_2[0]);

answered Nov 20, 2013 at 22:47

MattDiamant

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Comments

megawac · Accepted Answer · 2013-11-20 22:44:55Z

0

What you're asking for is Array.prototype.concat which combines two arrays (or more) into a new array. All you need is:

var array_3 = array_1.concat(array_2);

answered Nov 20, 2013 at 22:44

megawac

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