I have an array with a list of all controllers in my application:
$controllerlist = glob("../controllers/*_controller.php");
How do I strip ../controllers/ at the start and _controller.php at the end of each array element with one PHP command?
As preg_replace can act on an array, you could do:
$array = array(
"../controllers/test_controller.php",
"../controllers/hello_controller.php",
"../controllers/user_controller.php"
);
$array = preg_replace('~../controllers/(.+?)_controller.php~', "$1", $array);
print_r($array);
output:
Array
(
[0] => test
[1] => hello
[2] => user
)
Mapping one array to another:
$files = array(
'../controllers/test_controller.php',
'../controllers/hello_controller.php'
);
$start = strlen('../controllers/');
$end = strlen('_controller.php') * -1;
$controllers = array_map(
function($value) use ($start, $end) {
return substr($value, $start, $end);
},
$files
);
var_dump($controllers);
I'm not sure how you defined "command", but I doubt there is a way to do that with one simple function call.
However, if you're simply wanting it to be compact, here's a simple way of doing it:
$controllerlist = explode('|||', str_replace(array('../controllers/', '_controller.php'), '', implode('|||', glob("../controllers/*_controller.php"))));
It's a bit dirty, but it gets the job done in a single line.
$controllerlist = str_replace('../controllers/', '', glob("../controllers/*_controller.php")); $controllerlist = str_replace('_controller.php', '', $controllerlist);One command without searching and replacing? Yes you can!
If I'm not missing something grande, what about keeping it simple and chopping 15 characters from the start and the end using the substr function:
substr ( $x , 15 , -15 )
Since glob will always give you strings with that pattern.
Example:
// test array (thanks FruityP)
$array = array(
"../controllers/test_controller.php",
"../controllers/hello_controller.php",
"../controllers/user_controller.php" );
foreach($array as $x){
$y=substr($x,15,-15); // Chop 15 characters from the start and end
print("$y\n");
}
Output:
test
hello
user
substr_replace?$array = substr_replace(substr_replace($array,'',-15),'',0,15)No need for regex in this case unless there can be variations of what you mentioned.
$array = array(
"../controllers/test_controller.php",
"../controllers/hello_controller.php",
"../controllers/user_controller.php"
);
// Actual one liner..
$list = str_replace(array('../controllers/', '_controller.php'), "", $array);
var_dump($array);
This will output
array (size=3)
0 => string 'test' (length=4)
1 => string 'hello' (length=5)
2 => string 'user' (length=4)
Which is (I think) what you asked for.
If you have an array like this :
$array = array( "../controllers/*_controller.php",
"../controllers/*_controller.php");
Then array_map() help you to trim the unnecessary string.
function trimmer( $string ){
return str_replace( "../controllers/", "", $string );
}
$array = array( "../controllers/*_controller.php",
"../controllers/*_controller.php");
print_r( array_map( "trimmer", $array ) );
to strip 15 chars at the start and 15 at the end of each arrayelement in one command:
$controllerlist = substr_replace(
substr_replace(
glob("../controllers/*_controller.php"),'',-15
),'',0,15
)
preg_replace accepts an array as argument too:
$before = '../controllers/';
$after = "_controller.php";
$preg_str = preg_quote($before,"/").'(.*)'.preg_quote($after,"/");
$controllerlist = preg_replace('/^'.$preg_str.'$/', '\1', glob("$before*$after"));
array('../controllers/test_controller.php', '../controllers/hello_controller.php');