Jquery ajax return error

Question

I am using this ajax function

function testfunction(ttl){

        jQuery.ajax({url:"",
           type: "POST",
           data: { 'action_sub':'Load_twittercontact'},
           success:function(res){

                  //Do something

         },error:function(e){
                console.log(e.error);

        }});
    }

After some time , i got a error in error conolse. This is the error

function (){if(!d){var c=arguments,g,h,i,j,k;b&&(k=b,b=0);for(g=0,h=c.length;g<h;g++)i=c[g],j=f.type(i),j==="array"?e.done.apply(e,i):j==="function"&&a.push(i);k&&e.resolveWith(k[0],k[1])}return this}

How to solve this issue ?

please provide the error you are getting, not the source code — Sunil Verma
– Sunil Verma, Commented Nov 22, 2013 at 6:18
This is the error which i got in chrome console function (){if(u){var t=u.length;(function i(t){b.each(t,function(t,n){var r=b.type(n);"function"===r?e.unique&&p.has(n)||u.push(n):n&&n.length&&"string"!==r&&i(n)})})(arguments),n?o=u.length:r&&(s=t,c(r))}return this} — Sino Thomas
– Sino Thomas, Commented Nov 22, 2013 at 6:36
also this arguments: null caller: null length: 0 name: "" prototype: Object proto: function Empty() {} apply: function apply() { [native code] } arguments: null bind: function () { bindAsEventListener: function (object) { call: function call() { [native code] } caller: null constructor: function Function() { [native code] } length: 0 name: "Empty" toString: function toString() { [native code] } proto: Object — Sino Thomas
– Sino Thomas, Commented Nov 22, 2013 at 6:38

Ali Azam · Accepted Answer · 2013-11-22 06:45:18Z

1

Your error handler definition should be like the following code:

error: function(requestObject, error, errorThrown) { }

And to know what exactly happened, you should log the error parameter, like the following code:

error: function(requestObject, error, errorThrown) {
     console.log(error);
}

Hope this helps.

answered Nov 22, 2013 at 6:45

Ali Azam

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2 Comments

Sino Thomas Over a year ago

Thanks..I tried this and i got this error: "error" errorThrown: ""

Sino Thomas Over a year ago

I got this error only in Google chrome. In all other browsers it is working fine. Can you help me to solve this issue in Google chrome ?

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