I can't seem to figure out the regex pattern for matching strings only if it doesn't contain whitespace. For example
"this has whitespace".match(/some_pattern/)
should return nil but
"nowhitespace".match(/some_pattern/)
should return the MatchData with the entire string. Can anyone suggest a solution for the above?
In Ruby I think it would be
/^\S*$/
This means "start, match any number of non-whitespace characters, end"
\n and \r are also considered white space characters.
/\A\S*\Z/ instead, as this will match the start and end of the string rather than the start and end of lines. "lineone\nlinetwo" matched with /^\S*$/ will return "lineone"
You could always search for spaces, an then negate the result:
"str".match(/\s/).nil?
>> "this has whitespace".match(/^\S*$/)
=> nil
>> "nospaces".match(/^\S*$/)
=> #<MatchData "nospaces">
^ = Beginning of string
\S = non-whitespace character, * = 0 or more
$ = end of string
Not sure you can do it in one pattern, but you can do something like:
"string".match(/pattern/) unless "string".match(/\s/)
"nowhitespace".match(/^[^\s]*$/)
You want:
/^\S*$/
That says "match the beginning of the string, then zero or more non-whitespace characters, then the end of the string." The convention for pre-defined character classes is that a lowercase letter refers to a class, while an uppercase letter refers to its negation. Thus, \s refers to whitespace characters, while \S refers to non-whitespace.
str.match(/^\S*some_pattern\S*$/)
