Adding an element to a pre-initialized list in Java

Question

If I want to define a list of strings containing three items "Larry", "Curly" and "Moe"; and then later on I want to add "Shemp" to this list, is there any way to do this, which does not involve the use of 4 separate adds? What's the best way to complete this operation?

Edited for clarification: I'm using this list of 4 items as an example. In my actual program I need to create a much larger list (hence, why I am looking for a less cumbersome method). And the primary objective is that I would like to define some of the elements of the list right in when I am initializing it, but I also need to add a few elements to the list later on in the code.

Use ArrayList with add method.

Masudul
– Masudul

2013-11-25 10:33:09 +00:00
Commented Nov 25, 2013 at 10:33 — Masudul
– Masudul, Commented Nov 25, 2013 at 10:33

Ruchira Gayan Ranaweera · Accepted Answer · 2013-11-25 10:35:01Z

4

You can try this. But what is the issue with use of four add?

    List<String> list=new ArrayList<>();
    list.addAll(Arrays.asList("Larry","Curly","Moe","Shemp"));

answered Nov 25, 2013 at 10:35

Ruchira Gayan Ranaweera

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Shisa Over a year ago

Sorry, I need to add items to my list later on in the code, not all 4 at once)

Alexis C. · Accepted Answer · 2013-11-25 10:34:56Z

2

I want to define a list of strings containing three items "Larry","Curly" and "Moe" [....] is there any way to do this, which does not involve the use of 4 separate adds ?

You can use the constructor ArrayList(Collection<? extends E> c)

List<String> list = new ArrayList<>(Arrays.asList("Larry","Curly","Moe"));

and then later on I want to add "Shemp" to this list

Use the add method :

list.add("Shemp");

answered Nov 25, 2013 at 10:34

Alexis C.

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Developer Marius Žilėnas · Accepted Answer · 2013-11-25 10:39:02Z

1

Define a list:

List<String> list = new ArrayList<String>(
    Arrays.asList("Larry", "Curly", "Moe"));

then when you later want to add "Shemp" do:

list.add("Shemp");

answered Nov 25, 2013 at 10:39

Developer Marius Žilėnas

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Madhura · Accepted Answer · 2013-11-25 10:38:11Z

0

List<String> myList= new ArrayList<String>(Arrays.asList("Larry","Curly", "Shemp", "Moe"));

answered Nov 25, 2013 at 10:38

Madhura

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