How to count the number of values in this java program?

Question

This java program generates a random number between 1-6. It also allows the user to choose how many random numbers between 1-6 to generate. I now need to record and output how many instances of each number came up. ie. How many times each number 1,2,3,4,5,6 came up in a single run of the program. How would I go about doing this? Here is what I have so far.

import java.util.Random;

public class DiceRandomness {
    public static void main(String[] args) {
        Random generator = new Random();

        System.out.print("How many throws of the dice: ");
        int num = Console.readInt();

        int[] Results = new int[10000];

        for (int i = 0; i < num; i++) {

            int d = 1 + generator.nextInt(6);
            System.out.println(d + " ");
        }
    }
}

I'd create an array of 6 ints and increment the array entry corresponding to the number picked. — Hot Licks
– Hot Licks, Commented Nov 26, 2013 at 18:58
or 7 to avoid the off by one - and just use counter[result] instead of counter[result-1] — Glenn Teitelbaum
– Glenn Teitelbaum, Commented Nov 26, 2013 at 19:01

Martijn Courteaux · Accepted Answer · 2013-11-26 19:00:17Z

4

Hopefully this hint will help you:

int[] counters = new int[6];
for (int i = 0; i < num; ++i)
{

}

answered Nov 26, 2013 at 19:00

Martijn Courteaux

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3 Comments

Glenn Teitelbaum Over a year ago

@PeterLawrey that looks familiar

Martijn Courteaux Over a year ago

@PeterLawrey: That would be a huge memory waste :P

Peter Lawrey Over a year ago

@MartijnCourteaux but save some -1 and +1 in places.

Joe · Accepted Answer · 2013-11-26 19:04:32Z

0

Instead of storing the random number in d, store it to the Results array "Results[i]" that way each answer will get stored in the next index of the array.

Then put the print statement in a seperate for loop to print out the results.

answered Nov 26, 2013 at 19:04

Joe

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